Question

HELP, 35 POINTS! What is the equation of the circle in general form?

Answer 1

I think its c.

C. x2 + y2 + 4x + 2y − 2 = 0

Answer 2

Answer:

The equation of the given circle in general form is given by:

                   Option: A

               $x^2+y^2+4x+2y-44=0$

Step-by-step explanation:

We know that the general equation of a circle with center at (h,k) and radius 'r' is given by:

                    $(x-h)^2+(y-k)^2=r^2$

Clearly from the figure we have:

The center of the circle is at (-2,-1) and radius is 7 units.

i.e. we have: (h,k)=(-2,-1) and r=7

Hence, the equation of the circle is given by:

$(x-(-2))^2+(y-(-1))^2=7^2\\\\\\(x+2)^2+(y+1)^2=49$

on expanding the terms we have:

$x^2+4+4x+y^2+1+2y=49\\\\\\x^2+y^2+4x+2y+5-49=0\\\\\\x^2+y^2+4x+2y-44=0$

         Hence, the general equation of the circle is:

                    $x^2+y^2+4x+2y-44=0$