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cricket20 [7]
2 years ago
10

Write a do-while loop that continues to prompt a user to enter a number less than 100, until the entered number is actually less

than 100. End each prompt with newline Ex: For the user input 123, 395, 25, the expected output is:

Computers and Technology
2 answers:
nataly862011 [7]2 years ago
4 0

Complete Question:

Write a do-while loop that continues to prompt a user to enter a number less than 100, until the entered number is actually less than 100. End each prompt with a newline. Ex: For the user input 123, 395, 25, the expected output is:

Enter a number (<100):

Enter a number (<100):

Enter a number (<100):

Your number < 100 is: 25

Answer:

import java.util.Scanner;

public class num8 {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       int n;

       do{

           System.out.println("Enter a number (<100):");

           n= in.nextInt();

       }while(n>100);

       System.out.println("Your number < 100 is: "+n);

   }

}

Explanation:

Using Java programming language

Import the scanner class to receive user input

create an int variable (n) to hold the entered value

create a do while loop that continuously prompts the user to enter a number less than 100

the condition is while(n>100) It should continue the loop (prompting the user) until a number less than 100 is entered.

lara [203]2 years ago
4 0

Answer:

do{

           System.out.println("Enter a number (<100):");

           userInput = scnr.nextInt();

        } while(userInput > 100);

Explanation:

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Write a function called count_occurrences that takes two strings. The second string should only be one character long. The funct
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Answer:

Here is the Python function:

def count_occurrences (string1 , string2):  # method that takes two strings as parameter and returns how many times second string occurs in first

   count = 0  #counts number of occurrence of string2 in string1

   for word in string1:  #iterates through each word of the string1

       for character in word:  #iterates through each character of each word in string1

           if character == string2:  # checks if the character in string1 is equal to the character of string2

               count = count + 1  #adds 1 to the count of string2 in string1

   return count  #returns number of times the string2 occurs in string1

#in order to check the working of the function add the following lines to the code:    

first_str = input("Enter the first string: ")  #prompts user to enter first string

second_str = input("Enter the second string (one character long): ") #prompts user to enter second string which should be one character long

occurrence = count_occurrences(first_str,second_str)  #calls count_occurrences method by passing both strings to it

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Explanation:

The program is well explained in the comments added to each statement of the above code. I will explain the program with an example:

Suppose

string1 = "hello world"

string2 = 'l'

So the method count_occurrences() should return how many times l occurs in hello world.

count is used to count the number of occurrences of l in hello world. It is initialized to 0.

The first loop iterates through each word of string1. The first word of string1 is "hello"

The second loop iterates through each character/letter of each word. So the first letter of "hello" word is 'h'.

The if condition if character == string2: checks if the character is equal to string2 i.e. l.

character = "h"

string2 = "l"

The are not equal so the program moves to the next character of word hello which is e. The if condition again evaluates to false because e is not equal to l. So the program moves to the next character of word hello which is l.

This time the if condition evaluates to true because

character = "l"

string2 = "l"

character == string2

l == l

So the if part is executed which has the following statement:

count = count + 1

So the count is added to 1. count was 0 previously. Now

count = 1

Next the program moves to the next character of word hello which is l. This time the if condition evaluates to true because the character l matches with string2. So count is again incremented to 1. count = 2.

Next the program moves to the next character of word hello which is o. The if condition evaluates to false as o does not match with string2 i.e. l. So the count remains 2.

Next the first loop moves to the next word of the string1 = "world". The inner (second) for loop iterates through each character of "world" from "w" to "d" and checks if any character is equal to string2. Only one character is equal to string2 in "world". So count is incremented to 1. Hence count = 3

After the loop ends the statement return count returns the number of times string2 occurs in the string1. So the output is:

l occurs 3 times in hello world  

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