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4 years ago

HELP ME ASAP!!! PLZ PLZ

Mathematics

1 answer:

DanielleElmas [232]4 years ago

4 0

-5/8n= -0.4
Divde both sides by -5/8
n = 0.64

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If RX=4 and XS=9, then XT=<br> And how do you get it?

konstantin123 [22]

Answer:

XT=6 units

Step-by-step explanation:

The picture of the question is the attached figure

step 1

In the right triangle RST

Applying the Pythagorean theorem

$RS^2=RT^2+TS^2$

we have

$RS=RX+XS=4+9=13\ units$ ---> by segment addition postulate

substitute

$RT^2+TS^2=169$ ----> equation A

step 2

In the right triangle RTX

Applying the Pythagorean theorem

$RT^2=RX^2+XT^2$

we have

$RX=4\ units$

substitute

$RT^2=4^2+XT^2$

$RT^2=16+XT^2$

$XT^2=RT^2-16$ ----> equation B

step 3

In the right triangle XTS

Applying the Pythagorean theorem

$TS^2=XS^2+XT^2$

we have

$XS=9\ units$

substitute

$TS^2=9^2+XT^2$

$TS^2=81+XT^2$

$XT^2=TS^2-81$ ----> equation C

step 4

equate equation B and equation C

$TS^2-81=RT^2-16$

$TS^2-RT^2=81-16$

$TS^2-RT^2=65$ ----> equation D

step 5

Solve the system

$RT^2+TS^2=169$ ----> equation A

$TS^2-RT^2=65$ ----> equation D

Solve by elimination

Adds equation A and equation D

$RT^2+TS^2=169\\TS^2-RT^2=65\\---------\\TS^2+TS^2=169+65\\2TS^2=234\\TS^2=117$

Find the value of RT^2

$RT^2+117=169\\RT^2=52$

step 6

Find the value of XT

equation C

$XT^2=117-81\\XT^2=36\\XT=6\ units$

7 0

3 years ago

I need help please as soon as possible

frez [133]

B is the correct answer for this question

8 0

3 years ago

A prism has a volume of 64. If the dimensions of the prism are tripled, what is the volume of the new prism?

stepladder [879]

Answer:

C 1728

Step-by-step explanation:

since a volume always goes with the cubic (power of 3) units, tripling all dimensions (in all 3 dimensions / coordinate directions) puts this factor of 3 also to the power of 3 = 27

so, the volume increases by the factor of 27.

64×27 = 1728

5 0

3 years ago

3m-5m-12=7m-88-5<br><br> plz show all work

hammer [34]

3m - 5m - 12 = 7m - 88 - 5

-2m - 12 = 7m - 88 - 5

-2m - 12 = 7m - 93

-12 = 7m - 93 + 2m

-12 = 9m - 93

-12 + 93 = 9m

81 = 9m

9 = m

hope that helps, God bless!

3 0

4 years ago

The tires of a go-kart are 1 m in circumference. The tires revolve 15 times per second.

Goryan [66]

Answer:

600

Step-by-step explanation:

The circumference of a tire is the distance around it. The distance around these tires is 1 m. Since the tires revolve 15 times per second, this means every second the tires travel 15 m. This means that in 40 seconds, the tires travel15(40) = 600 m.

15 x 40 = 600

4 0

4 years ago

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