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horrorfan [7]
3 years ago
12

HELP ME ASAP!!! PLZ PLZ

Mathematics
1 answer:
DanielleElmas [232]3 years ago
4 0
-5/8n= -0.4
Divde both sides by -5/8
n = 0.64
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.......................answer
irakobra [83]

Answer:

d. 12xy

Step-by-step explanation:

The + signs separate terms.

3 0
3 years ago
Every 8th customer gets a $50 gift certificate.
cluponka [151]
The answer is the 24th customer
You need to find the LCM of 6 and 8.
If you prime factorize both you get…
6=(2)(3)
8=2^3
So 2^3, which is 8 times 3 is 24.
The answer is the 24th customer.
3 0
3 years ago
Solve the following equation:<br> V= 2(ab+bc+ca), for a
Nadya [2.5K]

V = 2ab + 2ca + 2bc

2ab + 2ca = V - 2bc

2a * b + c = V - 2bc

Answer: a = v - 2bc / 2 * b + c



Hope that helps!!!!! : )

8 0
4 years ago
Calculate the total area of the shaded region.
LUCKY_DIMON [66]

so hmmm seemingly the graphs meet at -2 and +2 and 0, let's check

\stackrel{f(x)}{2x^3-x^2-5x}~~ = ~~\stackrel{g(x)}{-x^2+3x}\implies 2x^3-5x=3x\implies 2x^3-8x=0 \\\\\\ 2x(x^2-4)=0\implies x^2=4\implies x=\pm\sqrt{4}\implies x= \begin{cases} 0\\ \pm 2 \end{cases}

so f(x) = g(x) at those points, so let's take the integral of the top - bottom functions for both intervals, namely f(x) - g(x) from -2 to 0 and g(x) - f(x) from 0 to +2.

\stackrel{f(x)}{2x^3-x^2-5x}~~ - ~~[\stackrel{g(x)}{-x^2+3x}]\implies 2x^3-x^2-5x+x^2-3x \\\\\\ 2x^3-8x\implies 2(x^3-4x)\implies \displaystyle 2\int\limits_{-2}^{0} (x^3-4x)dx \implies 2\left[ \cfrac{x^4}{4}-2x^2 \right]_{-2}^{0}\implies \boxed{8} \\\\[-0.35em] ~\dotfill

\stackrel{g(x)}{-x^2+3x}~~ - ~~[\stackrel{f(x)}{2x^3-x^2-5x}]\implies -x^2+3x-2x^3+x^2+5x \\\\\\ -2x^3+8x\implies 2(-x^3+4x) \\\\\\ \displaystyle 2\int\limits_{0}^{2} (-x^3+4x)dx \implies 2\left[ -\cfrac{x^4}{4}+2x^2 \right]_{0}^{2}\implies \boxed{8} ~\hfill \boxed{\stackrel{\textit{total area}}{8~~ + ~~8~~ = ~~16}}

7 0
2 years ago
Find each equation and then graph the line. x 2y=8
daser333 [38]
Y=8/2
y=4!!!!!!!!!!!!!!!!!
7 0
3 years ago
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