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snow_tiger [21]
2 years ago
4

2. Researchers are designing an experiment to compare two diferenst types of running shoes, A and B, to investigate which type i

s better for minimizing running time for a one-mile run. The experiment will consist of distributing design is planned, with blocking by classification of runner. Random samples of 50 professional runners and wear either the type A shoe or the type B shoe, and their running times will be recorded for a one-mile run. (a) What is a statistical advantage of blocking by the classification of runner? the shoes to runners who are classified as either professional or recreational. A randomized block unners will be selected. Each runner within each classification will be randomly assigned to Blocana by the classi (b) Why is it important to randomize the type of shoe the runner will wear instead of allowing the runner to choose the shoe? GO ON TO THE NEXT PAGE. EER Describe the shape of a histogram created from the data of the two s of students combined. With no ndicaion oF ourliers A crnitr berwen 96-10 s. The data nas a epiend of tom veseun 35-15 avou 80. (e) Consider the pogulation of all tudents in honors biokogy classes in the high school's state who are given the times has a shape similar to the combined histogram of students at the high school, with mean 70 minutes and standard deviation 26.5 minutes. For random samples of 50 students taken from the population, describe the sampling distribution of the sample mean completion time. task of using the spreadsheet program to investigate the topic in genetics. The distribution of the completion GO ON TO THE NEXT PAGE eny part of this page egat 7-
Mathematics
1 answer:
Len [333]2 years ago
8 0

Answer:

2 a) In Randomized Block design there are two variables one is a blocking variable the other one will be the treatment variable. Here type of shoes is the treatment variable and the type of runner is the blocking variable. Blocking is the arrangement of subjects similar in certain characteristics in to a group. Here professional runners are different from recreational runners . Blocking is done to reduce variability within groups so that variability within blocks is less than the variability between blocks. Then, subjects within each block are randomly assigned one of the shoes.

b) Randomization is the process of assigning participants a specific treatment  so that each participant has an equal chance of being assigned a shoe A or B. Randomization is done using random number generation and assignment is made according to the random numbers The main purpose of randomization is to eliminate biases. If the person in a group are allowed to choose the shoes they may choose their preferred one based on their past experience of using it or one variety will be preferred by most of the subjects in the group spoiling the entire purpose of the study. for e.g a group of professionals coming from a particular region prefers type A . If randomization is employed in such a situation almost half of the professionals coming from a particular region gets type A and the other half may get type B thus eliminating the personal biases in choice. This way we can eliminate any possible biases that may arise in the experiment. So randomization and blocking are important for a randomized block design in order to minimize bias in the responses.

Step-by-step explanation:

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An indoor water park has two giant buckets that slowly fill with 1000 gallons of water before dumping it on the people below. On
Art [367]

Answer:

The next two times both buckets dump water at the same time are 4:54 P.M and 7:18 P.M.

Step-by-step explanation:

From the question, one bucket dumps water every 18 minutes, say bucket A;

and the other bucket dumps water every 16 minutes, say bucket B.

Also, It is currently 2:45 P.M. and both buckets dumped water 15 minutes ago,

that is, both buckets dumped water at 2:30 P.M.

For bucket A, the next times it will dump water will be:

2:48 P.M, 3:06 P.M, 3:24 P.M, 3:42 P.M, 4:00 P.M, 4:18 P.M, 4:36 P.M, 4:54 P.M, 5:12 P.M, 5:30 P.M, 5:48 P.M, 6:06 P.M, 6:24 P.M, 6:42 P.M, 7:00 P.M, 7:18 P.M, 7:36 P.M, 7:54 P.M, 8:12 P.M, 8:30 P.M etc.

For bucket B, the next times it will dump water will be:

2:46 P.M, 3:02 P.M, 3:18 P.M, 3:34 P.M, 3:50 P.M, 4:06 P.M, 4:22 P.M, 4:38 P.M, 4:54 P.M, 5:10 P.M, 5:26 P.M, 5:42 P.M, 5:58 P.M, 6:14 P.M, 6:30 P.M, 6:46 P.M, 7:02 P.M, 7:18 P.M, 7:34 P.M, 7:50 P.M etc.

From above, we observe that the next two times both buckets dump water at the same time are 4:54 P.M and 7:18 P.M.

Hence, the next two times both buckets dump water at the same time are 4:54 P.M and 7:18 P.M.

6 0
2 years ago
Find the equation of a line in slope-intercept form, containing the points (9,2.6) and (8,2.2).
Zolol [24]
The equation in slope-intercept form would be y = 0.4x - 1

hope this helps!!
4 0
3 years ago
What is 2 to the power of 2?
padilas [110]
Okay, so you are talking about exponents, so what you are talking about is 2², to find the answer to the exponent you multiply the same number as many times as the exponent (little number) says, so in here we are going to multiply 2 x 2 and the answer is 4. So 2 to the power of 2 is 4.
5 0
3 years ago
7. The ratio of the weight of cement to the weight of sand in a concrete mixture is 1:3.
kondaur [170]
1 3 6 concrete ratio
Concrete
Proportions by Cement No. of 50 kg Sand to total aggregate
1:3:6 4.0 31
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4 0
3 years ago
The mean points obtained in an aptitude examination is 159 points with a standard deviation of 13 points. What is the probabilit
Korolek [52]

Answer:

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

Step-by-step explanation:

To solve this question, we have to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, a large sample size can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 159, \sigma = 13, n = 60, s = \frac{13}{\sqrt{60}} = 1.68

What is the probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled?

This is the pvalue of Z when X = 159+1 = 160 subtracted by the pvalue of Z when X = 159-1 = 158. So

X = 160

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{160 - 159}{1.68}

Z = 0.6

Z = 0.6 has a pvalue of 0.7257

X = 150

Z = \frac{X - \mu}{s}

Z = \frac{158 - 159}{1.68}

Z = -0.6

Z = -0.6 has a pvalue of 0.2743

0.7257 - 0.2743 = 0.4514

0.4514 = 45.14% probability that the mean of the sample would differ from the population mean by less than 1 point if 60 exams are sampled

7 0
3 years ago
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