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3 years ago

14

kelly is training for one marathon in week one she runs 7 miles in week two she runs 10 miles in week 3 she runs 13 miles given

that she keeps the same pattern find the total distance kelly has run after practicing for 7 weeks

1 answer:

Usimov [2.4K]3 years ago

7 0

Answer:

25 miles on week 7

Step-by-step explanation:

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The sum of two rational numbers will always be

Ostrovityanka [42]

The sum of two rational numbers will always be <u>rational</u>

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$\frac{a}{b} +\frac{c}{d} =\frac{ad+bc}{bd}$ , therefore it will always be rational

7 0

2 years ago

Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side

lorasvet [3.4K]

Answer:

Step-by-step explanation:

1.

cot x sec⁴ x = cot x+2 tan x +tan³x

L.H.S = cot x sec⁴x

=cot x (sec²x)²

=cot x (1+tan²x)² [ ∵ sec²x=1+tan²x]

= cot x(1+ 2 tan²x +tan⁴x)

=cot x+ 2 cot x tan²x+cot x tan⁴x

=cot x +2 tan x + tan³x [ ∵cot x tan x $=\frac{ \textrm{tan x }}{\textrm{tan x}}$ =1]

=R.H.S

2.

(sin x)(tan x cos x - cot x cos x)=1-2 cos²x

L.H.S =(sin x)(tan x cos x - cot x cos x)

= sin x tan x cos x - sin x cot x cos x

$=\textrm{sin x cos x }\times\frac{\textrm{sin x}}{\textrm{cos x} } - \textrm{sinx}\times\frac{\textrm{cos x}}{\textrm{sin x}}\times \textrm{cos x}$

= sin²x -cos²x

=1-cos²x-cos²x

=1-2 cos²x

=R.H.S

3.

1+ sec²x sin²x =sec²x

L.H.S =1+ sec²x sin²x

= $1+\frac{{sin^2x}}{cos^2x}$ [ $\textrm{sec x}=\frac{1}{\textrm{cos x}}$ ]

=1+tan²x $[\frac{\textrm{sin x}}{\textrm{cos x}} = \textrm{tan x}]$

=sec²x

=R.H.S

4.

$\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}} = \textrm{2 csc x}$

L.H.S= $\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}}$

$=\frac{\textrm{sinx(1+cos x)+{\textrm{sinx(1-cos x)}}}}{\textrm{(1-cos x)\textrm{(1+cos x})}}$

$=\frac{\textrm{sinx+sin xcos x+{\textrm{sinx-sin xcos x}}}}{{(1-cos ^2x)}}$

$=\frac{\textrm{2sin x}}{sin^2 x}$

= 2 csc x

= R.H.S

5.

-tan²x + sec²x=1

L.H.S=-tan²x + sec²x

= sec²x-tan²x

= $\frac{1}{cos^2x} -\frac{sin^2x}{cos^2x}$

$=\frac{1- sin^2x}{cos^2x}$

$=\frac{cos^2x}{cos^2x}$

=1

8 0

3 years ago

StartFraction 12 minus 3 y Over 2 EndFraction plus y StartFraction 2 y minus 4 Over y EndFraction for y = 3.

Neko [114]

Answer:
Step-by-step explanation:
The point slope form of the equation is expressed as
y - 7/2 = 1/2(x - 4)
Comparing with the point slope form of an equation which is expressed as
y - y1 = m(x - x1)
m represents slope
Therefore
m = 1/2
y1 = 7/2
x1 = 4
The slope intercept form of the equation of a straight line is expressed as
y = mx + c
Where c represents the intercept
Substituting y = 7/2, m = 1/2 and x = 4 into y = mx + c, it becomes
7/2 = 1/2 × 4 + c
7/2 = 2 + c
c = 2 - 7/2 = (4 - 7)/2 = - 3/2
Therefore, the y intercept is - 3/2

7 0

3 years ago

Read 2 more answers

-X + 5 = 1<br> What is the answer for this equation and the steps

jekas [21]

Answer:

x=4

Step-by-step explanation:

-x=1-5 (subtract 5 from both sides to isolate the x variable)

-x= -4 (1-5= -4)

x=4 (divide both sides by -1 so the x will not be a negative.)

Therefore, your answer will be x=4. Hope this helps! :)

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2 years ago

Read 2 more answers

Please help!!<br> Will mark brainliest

Over [174]

Y would equal to -5. hope this helps

8 0

2 years ago