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3 years ago

14

kelly is training for one marathon in week one she runs 7 miles in week two she runs 10 miles in week 3 she runs 13 miles given

that she keeps the same pattern find the total distance kelly has run after practicing for 7 weeks

1 answer:

Usimov [2.4K]3 years ago

7 0

Answer:

25 miles on week 7

Step-by-step explanation:

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GalinKa [24]

Answer:

1.

Volume= 729cm^3

Height= 9cm^2

Area of Base= 81cm^2

2.

Volume=450m^3

Height= 3m^2

Area of Base=150m^2

3.

Volume= 480 cm^2

Area of base=75cm^2

Height= 8cm^2

4.

Volume =120in^3

Area of Base=20in^2

Height= 6in^2

Step-by-step explanation:

Volume = (length) Times (Width) Times (Height)

Area os base = (Length) Times (width)

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The denominator of a fraction exceeds the numerator by 7. If 3 is added to the numerator and 1 is subtracted from the denominato

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Hey there. find an image attached.

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Find the percent of change on an item that was $44 and now costs $66.

iVinArrow [24]

Answer:

33.3%

Step-by-step explanation:

the increase in price was $22. Find the ratio

$22

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$66

which comes out to 0.33333, or 33.3%.

The percent change in the price of the item is 33.3%.

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3 years ago

Use the factors of the function and the y-intercept to find the standard form of the equation representing Jared’s function. Typ

Georgia [21]

The y-intercept of a function is the point where the graph crosses the $\mathbf{y = x^3 + 2x^2 - 193x - 270 }$

The factors of the Jared's graph are: (x - 10), (x + 3) and (x + 9)
The y-intercept is -13.5
The standard equation of the function is: $\mathbf{y = x^3 + 2x^2 - 193x - 270 }$

<u>(a) The factors</u>

First, we write out the points where the function cross the x-axis.

The points are:

$\mathbf{x = 10}$

$\mathbf{x = -3}$

$\mathbf{x = -9}$

Equate the above points to 0

$\mathbf{x -10 = 0}$

$\mathbf{x +3 = 0}$

$\mathbf{x +9 = 0}$

Hence, the factors are: (x - 10), (x + 3) and (x + 9)

<u>(b) The y-intercept</u>

This is the point where the graph crosses the y-axis.

From the attached graph, the graph crosses the y-axis at -13.5.

Hence, the y-intercept is -13.5

<u>(c) The standard form</u>

In (a), we have:

$\mathbf{x -10 = 0}$

$\mathbf{x +3 = 0}$

$\mathbf{x +9 = 0}$

Multiply the above equations

$\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 \times 0 \times 0}$

$\mathbf{(x - 10) \times (x + 3) \times (x + 9) = 0 }$

Expand

$\mathbf{(x - 10) \times (x^2 + 3x + 9x + 27) = 0 }$

$\mathbf{(x - 10) \times (x^2 + 12x + 27) = 0 }$

Expand

$\mathbf{x^3 + 12x^2 + 27x - 10x^2 - 220x - 270 = 0 }$

Collect like terms

$\mathbf{x^3 + 12x^2 - 10x^2+ 27x - 220x - 270 = 0 }$

$\mathbf{x^3 + 2x^2 - 193x - 270 = 0 }$

Replace 0 with y

$\mathbf{y = x^3 + 2x^2 - 193x - 270 }$

Hence, the standard form is: $\mathbf{y = x^3 + 2x^2 - 193x - 270 }$

Read more about graphs and functions at:

brainly.com/question/18806107

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3 years ago

#6 help needed with math

yarga [219]

Answer: Secant of angle A = √2

Step-by-step explanation:

From the given right angle triangle,

AB represents the hypotenuse of the right angle triangle.

With m∠B as the reference angle,

AC represents the adjacent side of the right angle triangle.

BC represents the opposite side of the right angle triangle.

To determine Cosine of m∠A, we would apply

the cosine trigonometric ratio.

Cos θ = adjacent side/hypotenuse. Therefore,

Cos A = √5/√10

Secant = 1/Cosine

Therefore,

Secant of angle A = √10/√5 = √2

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