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3 years ago

One minute is 1/60 of an hour. What part of an hour is 12 minutes?

Mathematics

2 answers:

a_sh-v [17]3 years ago

8 0

Answer:

12/60 but you want the simplified which is 1/5 or 20%

Alla [95]3 years ago

7 0

2/10ths of an hour. You do 12/60 and get 0.2

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One more then im done, ty ^^

OleMash [197]

Answer:

Step-by-step explanation:

5 0

2 years ago

Can someone explain to me how to solve this equation<br>15x +-6 = 8

soldier1979 [14.2K]

Answer:

x=0.933333

Step-by-step explanation:

First you add 6 to both sides of the equation

15x - 6 + 6 = 8 +6

That gives you 15x = 14

Then you divide 15 on both sides of the equation

That gives you x = 14/15 = 0.93333

8 0

4 years ago

Read 2 more answers

2(x-1) ≥ 10 or 3-4x > 15<br> Solve the compound inequality, and show work!

Veseljchak [2.6K]

Answer:

$x\geq 6\text{ or } x$

Step-by-step explanation:

We have the compound inequality:

$2(x-1)\geq10\text{ or } 3-4x>15$

Let's solve each of them individually first:

We have:

$2(x-1)\geq10$

Divide both sides by 2:

$x-1\geq5$

Add 1 to both sides:

$x\geq6$

We have:

$3-4x>15$

Subtract from both sides:

$-4x>12$

Divide both sides by -4:

$x$

Hence, our solution set is:

$x\geq 6\text{ or } x$

5 0

3 years ago

Read 2 more answers

(d) Mrs. Ferguson has a conversation on the phone with her best friend Judy, who stayed at the same hotel last year. They compar

faltersainse [42]

Rooms are 3 dimentional
they have volume
area times height=volume

if dimentions are the same, that means that the legnth, width, height are same, so therefor they have same area (Judy is correct)

if area area same, then the height could be different, so Mrs. Ferguson is wrong

Judy is correct and Mrs. Ferguson is wrong

8 0

3 years ago

Which shows the expression x^2-1/x^2-x in simplest form

____ [38]

Answer:

$\large\boxed{\dfrac{x+1}{x}=1+\dfrac{1}{x}}$

Step-by-step explanation:

$\dfrac{x^2-1}{x^2-x}=(*)\\\\x^2-1=x^2-1^2\qquad\text{use}\ a^2-b^2=(a-b)(a+b)\\=(x-1)(x+1)\\\\x^2-x=(x)(x)-(x)(1)\qquad\text{use the distributive property}\\=x(x-1)\\\\(*)=\dfrac{(x-1)(x+1)}{x(x-1)}\qquad\text{cancel}\ (x-1)\\\\=\dfrac{x+1}{x}=\dfrac{x}{x}+\dfrac{1}{x}=1+\dfrac{1}{x}$

4 0

3 years ago

Read 2 more answers