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2 years ago

4. For the Earth to get all the way around the Sun and back to where it started takes

Mathematics

2 answers:

victus00 [196]2 years ago

7 0

It takes 365 but if your doing this for the exact i would do 365.25 or 1/4 due to the leap year

PIT_PIT [208]2 years ago

4 0

It takes the Earth one year, or 365 1/4 days I think

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Use the equation y = 5/2 to complete the table. is y proportional to x and y? Explain why or why not

ivanzaharov [21]

Answer: Yes it is

Step-by-step explanation:

You have to take 2 times 5/2 witch is the same is 2.5

So 2.5 times 2

3 times 2.5

6 times 2.5 and that's how you get the answer

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2 years ago

WILL GIVE BRAINLIEST

wolverine [178]

I’m not 100% what kind of “order” it needs. But the picture the answer is D

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2 years ago

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Select the correct answer. Brianna begins the construction of square EGFH inscribed in circle C by drawing GH, a diameter of the

kaheart [24]

Answer:

B. "She should name the diameter she first drew EG and name the new segment FH."

Step-by-step explanation:

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1 year ago

Subtract the quotient of 18 and 2 from the sum of 22 and 9.

Elza [17]

The quastion is asking us to subtract the quotient of 18 and 2 from the sum of 22 and 9. Quotient of 18 and 2 = 18/2 = 18 : 2 = 9. Sum of 22 and 9 = 22 + 9 . And if we have to subtract 9 from 31 the solution is: 31 - 9 = 22. It can also be written like this: ( 22 + 9 ) - 18 / 2 = 31 - 9 = 22. Answer: 22<span>.</span>

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2 years ago

Evaluate cosA/2 given cosA=-1/3 and tanA >0

mote1985 [20]

Answer:

$\bold{cos\dfrac{A}{2} = -\dfrac{1}{\sqrt3}}$

Step-by-step explanation:

Given that:

$cosA=-\dfrac{1}3$

and

$tanA > 0$

To find:

$cos\dfrac{A}{2} = ?$

Solution:

First of all,we have cos value as negative and tan value as positive.

It is possible in the 3rd quadrant only.

$\dfrac{A}{2}$ will lie in the 2nd quadrant so $cos\dfrac{A}{2}$ will be negative again.

Because Cosine is positive in 1st and 4th quadrant.

Formula:

$cos2\theta =2cos^2(\theta) - 1$

Here $\theta = \frac{A}{2}$

$cosA =2cos^2(\dfrac{A}{2}) - 1\\\Rightarrow 2cos^2(\dfrac{A}{2}) =cosA+1\\\Rightarrow 2cos^2(\dfrac{A}{2}) =-\dfrac{1}3+1\\\Rightarrow 2cos^2(\dfrac{A}{2}) =\dfrac{2}3\\\Rightarrow cos(\dfrac{A}{2}) = \pm \dfrac{1}{\sqrt3}$

But as we have discussed, $cos\dfrac{A}{2}$ will be negative.

So, answer is:

$\bold{cos\dfrac{A}{2} = -\dfrac{1}{\sqrt3}}$

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2 years ago