Let the distance between the tree and the first point (point H) be x and let the height of the tree be h, then:
Also, the distance from the tree to the second point (point L) is x + 60, thus:
From (1) and (2), we have:
From (1):
h = x tan 40° = 132.4 (0.8391) = 111.1 feet.
Therefore, the height of the tree is 111.1 feet
Answer: Distance between line and point =
4√5 -3/2√10
Step-by-step explanation:
Distance between the line is
= √ ((9-0)²+(0+1)²)
= √ (89+1)
= √90
= 3√10
Half of the line = 3/2√10
Distance of one side of the line and the point.
= √((9-1)²+(0-4)²)
= √((8)²+(-4)²)
=√64+16
= √80
= 4√5
Distance between line and point =
4√5 -3/2√10
I think I got it. Correct me if I am wrong.
Parallelogram diagram I believe down below. We must find the height and then the area using Pythagorean theorem. Since the green shaded part is a 30-60-90 triangle, the base is 1/2 the hypotenuse, therefore it is 3. Now we calculate the height with it.
A^2 + B^2 = C^2
A^2 + 3^2 = 6^2
A^2 + 9 = 36
A^2 = 27
A = 3√3
Therefore the height is 3√3
Now calculate the area using A = bh
A = bh
= (12)(3√3)
= 36√3
So the area is 36√3 square units.
I cannot be sure of this answer because you did not provide a diagram.
256/625 is the answer I believe
Answer:
i think its y = x² + 6x - 55