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svet-max [94.6K]
3 years ago
13

What is 2x -3 + 8 solved

Mathematics
2 answers:
irga5000 [103]3 years ago
5 0

Answer:

2x + 5

Step-by-step explanation:

-3 + 8 = 5

+ 2x = 2x + 5

Hope this helps!

yKpoI14uk [10]3 years ago
3 0

Answer:

2x+5

Step-by-step explanation:

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Please help me with this
Marysya12 [62]

Answer:

SAS is the answer.........

5 0
3 years ago
The perimeter of a rectangle is 24 m. The length is 30 m less than five times the width. Find the dimensions of the rectangle. L
Len [333]

Answer:

<h2>width = 7 m</h2><h2>length = 5 m</h2>

Step-by-step explanation:

Perimeter of a rectangle = 2l + 2w

where

l is the length

w is the width

From the question

Perimeter = 24m

The statement

The length is 30 m less than five times the width is written as

l = 5w - 30

Substitute the expression into the above formula and solve for the width

That's

24 = 2( 5w - 30) + 2w

24 = 10w - 60 + 2w

84 = 12w

Divide both sides by 12

w = 7

Substitute this value into l = 5w - 30

That's

l = 5(7) - 30

l = 35 - 30

l = 5

Therefore the dimensions are

width = 7 m

length = 5 m

Hope this helps you

6 0
3 years ago
Navy PilotsThe US Navy requires that fighter pilots have heights between 62 inches and78 inches.(a) Find the percentage of women
Zigmanuir [339]

The first part of the question is missing and it says;

Use these parameters: Men's heights are normally distributed with mean 68.6 in. and standard deviation 2.8 in. Women's heights are normally distributed with mean 63.7 in. and standard deviation 2.9 in.

Answer:

A) Percentage of women meeting the height requirement = 72.24%

B) Percentage of men meeting the height requirement = 0.875%

C) Corresponding women's height =67.42 inches while corresponding men's height = 72.19 inches

Step-by-step explanation:

From the question,

For men;

Mean μ = 68.6 in

Standard deviation σ = 2.8 in

For women;

Mean μ = 63.7 in

Standard deviation σ = 2.9 in

Now let's calculate the standardized scores;

The formula is z = (x - μ)/σ

A) For women;

Z = (62 - 63.7)/2.9 = - 0.59

Z = (78 - 63.7)/2.9 = 4.93

The original question cam be framed as;

P(62 < X < 78).

So thus, the probability of only women will take the form of;

P(-0.59 < Z < 4.93) = P(Z<4.93) - P(Z > - 0.59)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<4.93) = 0.9999996

And P(Z > - 0.59) = 0.277595

Thus;

P(Z<4.93) - P(Z > - 0.59) =0.9999996 - 0.277595 = 0.7224

So, percentage of women meeting the height requirement is 72.24%.

B) For men;

Z = (62 - 68.6)/2.8 = -2.36

Z = (78 - 68.6)/2.8 = 3.36

Thus, the probability of only men will take the form of;

P(-2.36 < Z < 3.36) = P(Z<3.36) - P(Z > - 2.36)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<3.36) = 0.99961

And P(Z > -2.36) = 0.99086

Thus;

P(Z<3.36) - P(Z > -2.36) 0.99961 - 0.99086 = 0.00875

So, percentage of women meeting the height requirement is 72.24%.

B)For women;

Z = (62 - 63.7)/2.9 = - 0.59

Z = (78 - 63.7)/2.9 = 4.93

The original question cam be framed as;

P(62 < X < 78).

So thus, the probability of only women will take the form of;

P(-0.59 < Z < 4.93) = P(Z<4.93) - P(Z > - 0.59)

From the normal probability table attached, when we interpolate, we'll arrive at P(Z<4.93) = 0.9999996

And P(Z > - 0.59) = 0.277595

Thus;

P(Z<4.93) - P(Z > - 0.59) =0.9999996 - 0.277595 = 0.00875

So, percentage of women meeting the height requirement is 0.875%

C) Since the height requirements are changed to exclude the tallest 10% of men and the shortest10% of women.

For women;

Let's find the z-value with a right-tail of 10%. From the second table i attached ;

invNorm(0.90) = 1.2816

Thus, the corresponding women's height:: x = (1.2816 x 2.9) + 63.7= 67.42 inches

For men;

We have seen that,

invNorm(0.90) = 1.2816

Thus ;

Thus, the corresponding men's height:: x = (1.2816 x 2.8) + 68.6 = 72.19 inches

7 0
3 years ago
Six bags of Takis costs $13.50. Five bags of Takis costs $10. Which has
viktelen [127]

Answer:

the correct answer is 5 bags

4 0
3 years ago
Read 2 more answers
How do I construct a sample data set for which n=7, x=9(x bar), and s=0?
JulijaS [17]
When the standard deviation = 0, there is no deviation at all. So the numbers are all the same. And there are seven of them. And the average is nine. 
So the sample data set would just be seven 9s. 
4 0
3 years ago
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