I wanna say it would be 1 would be A 2 would be C 3 would be D 4 would be B and 5 would be E
hope this helps
Cells are the basic building blocks of all living things
2. Its showing that Customers who are in the Value X Rewards Program would also receive free popcorn or drinks each time they would shop at the store.
Hope this helped.
Answer:
237.8L of water would need to be added.
Explanation:
The first thing to do is to identify that the equation to be used is M1V1=M2V2. (This equation works because it turns everything into moles which can then be compared).
Then figure out what information you have and what is being found. In this case:
M1 = 54.7 M
V1 = 1092 mL = 1.092 L
M2 = 0.25 M
V2 = unknown
Then solve the equation for whatever you are trying to find.
M1V1=M2V2
V2=M1V1/M2
Now you need to plug everything in.
V2=(54.7M*1.091L)/0.25M
V2=238.93L
That means that the solution needs a volume of 238.7L to gain a molarity of 0.25M but the starting solution already had a volume of 1.092 L meaning that to find the amount of solvent that needs to be added you just subtract the starting volume by the volume that the solution needs to be.
238.93L - 1.091L = 237.8L
Therefore the answer is that 237.8L needs to be added to a 1.092L 54.7M NaCl solution to make the concentration 0.25M.
I hope this helps. Let me know if anything is unclear.
Answer:Methane gas is evolved from the reaction mixture.
Explanation:
When ethyl acetoacetate is treated with grignard reagent a carbanion is generated.
There are two acidic hydrogens which are present on the carbon which is in between the ester and the ketone group in ethylacetoacetate.
These two protons are also called active methylene protons and they are very acidic in nature due to the presence of two electron withdrawing substituents that is an ester and ketone.
CH₃MgBr is grignard reagent and it is an organo-metallic copmpound . Carbon here in CH₃MgBr exists as carbanion CH3⁻ which is basic enough to abstract the acidic protons present on ethylacetoacetate.
As CH3⁻ abstracts an acidic proton from ethylacetoacetate it become CH₄ which is methane. As methane is a gas so it is methane gas which is evolved from the reaction mixture.
As the acidic proton is abstracted from ethylacetoacetate which leads to generation of carbanion and this carbanion is very stable as it can be delocalized on to the two carbonyl groups . As we add aqueous acid to the reaction mixture the carbanion can again be protonated and its protonation would lead to the generation of ethylacetoacetate again.
