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puteri [66]
3 years ago
7

In a volumetric analysis experiment, an acidic aqueous solution of methanol (CH3OH) is titrated with a solution of potassium dic

hromate (K2Cr2O7) according to the following balanced chemical equation: 2K2Cr2O7(aq) + 8H2SO4(aq) + 3CH3OH(aq) → 2Cr2(SO4)3(aq) + 11H2O(l) + 3 HCOOH(aq) + 2K2SO4(aq) What volume of 0.00143 M K2Cr2O7 is required to titrate 1.90 g of CH3OH dissolved in 50.0 mL of solution
Chemistry
1 answer:
Lady bird [3.3K]3 years ago
5 0

Answer:

27.64 liters

Explanation:

From the balanced equation, 2 moles of K2Cr2O7 requires 3 moles of CH3OH.

Mole of CH3OH = 1.9/32.04 = 0.0593 mole

Mole of K2Cr2O7 that will require 0.0593 mole of CH3OH:

                   2 x 0.0593/3 = 0.0395 mole

mole = molarity x volume

Volume of K2Cr2O7 needed = 0.0395/0.00143

                             = 27.64 Liter

<em>Hence, 27.64 liters of 0.00143 M K2Cr2O7 will be required to titrate 1.90 g of CH3OH dissolved in 50.0 mL of solution</em>

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Answer:

89°C

Explanation:

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8.653846154 = 769.85/T₂

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3 years ago
How many grams of n2f4 can be produced from 225g f2?
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The answer is 615.91 grams of <span>n2f4

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4 years ago
Listed below are possible solutes. In your possession is a beaker with 500 milliliters of water. You want to make an aqueous sol
slavikrds [6]

Answer: I & III

Explanation:  Solutes are the substances which are minimum in quantity and which is required to dissolve in the solvent (which is larger in quantity) in order to make a solution.

In the asked question, it is given that the water is the solvent and from the given solutes we have to pick which would make an aqueous solution with the highest concentration of solute possible.

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8 0
4 years ago
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In compliance with conservation of energy, Einstein explained that in the photoelectric effect, the energy of a photon (hv) abso
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Answer:

 a) 1.866 × 10 ⁻¹⁹ J      b)   3.685 × 10⁻¹⁹ J

Explanation:

the constants involved are

h ( Planck constant) = 6.626 × 10⁻³⁴ m² kg/s

Me of electron = 9.109 × 10 ⁻³¹ kg

speed of light = 3.0 × 10 ⁸ m/s

a) the Ek ( kinetic energy of the dislodged electron) = 0.5 mu²

Ek = 0.5 × 9.109 × 10⁻³¹ × ( 6.40 × 10⁵ )² = 1.866 × 10 ⁻¹⁹ J

b) Φ ( minimum energy needed to dislodge the electron ) can be calculated by this formula

hv =   Φ + Ek

where Ek = 1.866 × 10 ⁻¹⁹ J

v ( threshold frequency ) = c / λ where c is the speed of light and λ is the wavelength of light = 358.1 nm = 3.581 × 10⁻⁷ m

v = ( 3.0 × 10 ⁸ m/s ) / (3.581 × 10⁻⁷ m ) = 8.378 × 10¹⁴ s⁻¹

hv = 6.626 × 10⁻³⁴ m² kg/s ×  8.378 × 10¹⁴ s⁻¹ = 5.551 × 10⁻¹⁹ J

5.551 × 10⁻¹⁹ J = 1.866 × 10 ⁻¹⁹ J + Φ

Φ = 5.551 × 10⁻¹⁹ J - 1.866 × 10 ⁻¹⁹ J = 3.685 × 10⁻¹⁹ J

7 0
3 years ago
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