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Ahat [919]
3 years ago
15

Why is potassium nitrate classified as aj electrolyte?

Chemistry
2 answers:
baherus [9]3 years ago
6 0
<span>KNO3 is a strong electrolyte because it completely dissociates into ions in water. Dissociates means it immediately breaks into ions of K+ (potassium cation) and NO3- (nitrate anion). Thus it also conducts electricity very well compared to a weak electrolyte.</span>
oee [108]3 years ago
4 0

Potassium Nitrate is classified as an electrolyte because of its highly conductive nature when dissolved in water.

Explanation

Potassium nitrate represented as KNO3 are ionic bonded compounds.

They are polar substances as the electronegative difference between nitrate and potassium is very high, so they can easily break their bond and dissolve in water easily.

It has large range of applications. It is even used as gun powder, in firecrackers etc,.

As the KNO3 is easily soluble in water and they can form K+ and NO3- ions when dissolved in water.

These ions acts as conducting agents in the water solution so they act as electrolyte.

As electrolytes are the solutions which have the capacity to conduct electrical energy in the electrochemical reactions, the conductive nature of potassium nitrate dissolved in water makes them useful as an electrolyte in salt bridge experiment.

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Determine the mole fractions and partial pressures of CO2, CH4, and He in a sample of gas that contains 1.20 moles of CO2, 1.79
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Answer :  The mole fraction and partial pressure of CH_4,CO_2 and He gases are, 0.267, 0.179, 0.554 and 1.54, 1.03 and 3.20 atm respectively.

Explanation : Given,

Moles of CH_4 = 1.79 mole

Moles of CO_2 = 1.20 mole

Moles of He = 3.71 mole

Now we have to calculate the mole fraction of CH_4,CO_2 and He gases.

\text{Mole fraction of }CH_4=\frac{\text{Moles of }CH_4}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

\text{Mole fraction of }CH_4=\frac{1.79}{1.79+1.20+3.71}=0.267

and,

\text{Mole fraction of }CO_2=\frac{\text{Moles of }CO_2}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

\text{Mole fraction of }CO_2=\frac{1.20}{1.79+1.20+3.71}=0.179

and,

\text{Mole fraction of }He=\frac{\text{Moles of }He}{\text{Moles of }CH_4+\text{Moles of }CO_2+\text{Moles of }He}

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Thus, the mole fraction of CH_4,CO_2 and He gases are, 0.267, 0.179 and 0.554 respectively.

Now we have to calculate the partial pressure of CH_4,CO_2 and He gases.

According to the Raoult's law,

p_i=X_i\times p_T

where,

p_i = partial pressure of gas

p_T = total pressure of gas  = 5.78 atm

X_i = mole fraction of gas

p_{CH_4}=X_{CH_4}\times p_T

p_{CH_4}=0.267\times 5.78atm=1.54atm

and,

p_{CO_2}=X_{CO_2}\times p_T

p_{CO_2}=0.179\times 5.78atm=1.03atm

and,

p_{He}=X_{He}\times p_T

p_{He}=0.554\times 5.78atm=3.20atm

Thus, the partial pressure of CH_4,CO_2 and He gases are, 1.54, 1.03 and 3.20 atm respectively.

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