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Effectus [21]
3 years ago
6

PLEASE HELP AND THANKS

Chemistry
1 answer:
Kamila [148]3 years ago
4 0

Answer:

torque =force*distance

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A type of plate boundary that is transform faults (easily seen where they cut at right angles to the mid-ocean ridges) A.) conve
34kurt
The answer is Option C (Divergent Plate Boundary)

Mapping efforts have shown that mid-ocean ridges<span> are discontinuous structures that cut at </span>right angles<span> to its length at various transform faults. They typically </span><span>demarcate the </span>boundary <span>between two tectonic plates, and are therefore called </span>divergent<span> plate </span>boundaries.
8 0
3 years ago
2. Differentiate the types of tectonic plates.
kramer

Answer:

Explanation:

Convergent boundaries: where two plates are colliding. Subduction zones occur when one or both of the tectonic plates are composed of oceanic crust. ...

Divergent boundaries – where two plates are moving apart. ...

Transform boundaries – where plates slide passed each other.

3 0
3 years ago
What's the boiling point of water at 0 atmospheric pressure?
nirvana33 [79]

Answer:

The water will evaporate and fly out of the bucket; the process will not stop until there is enough water vapor in the atmosphere that the vapor pressure stops the water from boiling further.

Explanation:

4 0
2 years ago
A 8.00 L tank at 26.9 C is filled with 5.53 g of dinitrogen difluoride gas and 17.3 g of sulfur hexafluoride gas. You can assume
pshichka [43]

Answer:

mole fraction of N_2 O = 0.330

mole of fraction SF_4 = 0.669

PRESSURE OF N_2 O = 39127.053 Pa

pressure of SF_4 = 792126.36

Total pressure   = 118253.413 Pa

Explanation:

Given data:

volume of tank 8 L

Weight of dinitrogen difluoride gas 5.53 g

weight of sulphur hexafluoride gas 17.3 g

Amount of N_2 O = \frac{5.53}{14*2 + 16} = 0.1256 mol

amount of SF_4 = \frac{17.3}{32.1 + 19*4} = 0.254 mol

mole fraction of N_2 O = \frac{0.1256}{0.1256 + 0.254} = 0.330

mole of fractionSF_4 = \frac{0.254}{0.1256 + 0.254} = 0.669

PV = nRT

P of N_2 O = \frac{0.1256 *8.31 (273 + 26.9}{0.008} = 39127.053 Pa

mole of SF_4=\frac{0.254 *8.31*(273+26.9)}{.008} = 79126.36 Pa

Total pressure  = 39127.053 + 79126.36 = 118253.413 Pa

6 0
3 years ago
Which must be the same when comparing 1 mol of oxygen gas, O2, with 1 mol of carbon monoxide gas, CO?
Julli [10]

Answer:

The number of molecules.

Explanation:

7 0
3 years ago
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