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Andre45 [30]
2 years ago
15

According to Boyle’s law, when the pressure of a gas increases at constant temperature, its volume

Chemistry
1 answer:
Leya [2.2K]2 years ago
4 0

Answer:

the volume increases

Explanation:

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Which subshells (s, p, d, f, or g) can have electrons with the indicated magnetic quantum number (ml)?
amm1812

Answer:

=3 means is 3 or greater so that would be f and g subshells

=0 means is 0 or greater so that would be s, p, d, f and g subshells

=1 means is 1 or greater so that would be p, d, f, and g subshells

=4 means is 4 or greater so that would be g only

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2 years ago
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At STP , how many molecules of nitrogen gas are in 2.24 L?
Oksanka [162]

Explanation:

At STP ,2.24 L contain 0.1 mole of N²

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2 years ago
What is the entropy change of the surroundings
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Answer: The entropy change of the surroundings will be -17.7 J/K mol.

Explanation: The enthalpy of vapourization for 1 mole of acetone is 31.3 kJ/mol

Amount of Acetone given = 10.8 g

Number of moles is calculated by using the formula:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of acetone = 58 g/mol

Number of moles = \frac{10.8}{58}=0.1862moles

If 1 mole of acetone has 32.3 kJ/mol of enthalpy, then

0.1862 moles will have = \frac{32.3}{1}\times 0.1862=5.828kJ/mol

To calculate the entropy change for the system, we use the formula:

\Delta S_{sys}=\frac{\Delta H_{vap}}{T(\text{ in K)}}

Temperature = 56.2°C = (273 + 56.2)K = 329.2K

Putting values in above equation, we get

\Delta S_{sys}=\frac{5.828}{329.2}=0.0177kJ/Kmol=17.7J/Kmol   (Conversion Factor: 1 kJ = 1000J)

At Boiling point, the liquid phase and gaseous phase of acetone are in equilibrium. Hence,

\Delta S_{system}+\Delta S_{surrounding}=0

\Delta S_{surrouding}=-\Delta S_{system}=-17.7J/Kmol

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3 years ago
The most common element in the atmosphere are
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Nitrogen and oxygen are the most prevalent in the atmosphere.
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3 years ago
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