1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Arte-miy333 [17]
3 years ago
6

Somebody please help me

Mathematics
1 answer:
Elan Coil [88]3 years ago
4 0
4x=6x-14

First isolate the variables onto one side and the numbers on the other so subtract 4x from both sides of the equation and add 14 to both sides of the equation to get 14=2x then you are going to want to completely isolate the variable so you divide 2 on both sides to get an answer of X=7
You might be interested in
Finding the Zeros
Romashka-Z-Leto [24]
Use the quadratic formula to solve the equations . you will get the answers 
5 0
3 years ago
Read 2 more answers
What is the y-interceptof the graph below?*
Talja [164]

Answer:

J- 2

Step-by-step explanation:

its where the line goes through the plot on the vertical axis

6 0
2 years ago
Read 2 more answers
Order each set of numbers from greatest to least square root 43, 3.6, -3 square root 2?
Alekssandra [29.7K]
√(43) = 6.55.
-3√(2) = -4.24...


√(43) > 3.6 > -3√(2)
4 0
3 years ago
~Please only answer if you know for sure~
Evgesh-ka [11]
20%.

20,000 times 0.8 is 16,000, so the decreased value that was lost was 20% of the original price.
7 0
3 years ago
Read 2 more answers
Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for each function.
Lunna [17]

Answer:

The first three nonzero terms in the Maclaurin series is

\mathbf{ 5e^{-x^2} cos (4x)  }= \mathbf{ 5 ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }

Step-by-step explanation:

GIven that:

f(x) = 5e^{-x^2} cos (4x)

The Maclaurin series of cos x can be expressed as :

\mathtt{cos \ x = \sum \limits ^{\infty}_{n =0} (-1)^n \dfrac{x^{2n}}{2!} = 1 - \dfrac{x^2}{2!}+\dfrac{x^4}{4!}-\dfrac{x^6}{6!}+...  \ \ \ (1)}

\mathtt{e^{-2^x} = \sum \limits^{\infty}_{n=0}  \ \dfrac{(-x^2)^n}{n!} = \sum \limits ^{\infty}_{n=0} (-1)^n \ \dfrac{x^{2n} }{x!} = 1 -x^2+ \dfrac{x^4}{2!}  -\dfrac{x^6}{3!}+... \ \ \  (2)}

From equation(1), substituting x with (4x), Then:

\mathtt{cos (4x) = 1 - \dfrac{(4x)^2}{2!}+ \dfrac{(4x)^4}{4!}- \dfrac{(4x)^6}{6!}+...}

The first three terms of cos (4x) is:

\mathtt{cos (4x) = 1 - \dfrac{(4x)^2}{2!}+ \dfrac{(4x)^4}{4!}-...}

\mathtt{cos (4x) = 1 - \dfrac{16x^2}{2}+ \dfrac{256x^4}{24}-...}

\mathtt{cos (4x) = 1 - 8x^2+ \dfrac{32x^4}{3}-... \ \ \ (3)}

Multiplying equation (2) with (3); we have :

\mathtt{ e^{-x^2} cos (4x) = ( 1- x^2 + \dfrac{x^4}{2!} ) \times ( 1 - 8x^2 + \dfrac{32 \ x^4}{3} ) }

\mathtt{ e^{-x^2} cos (4x) = ( 1+ (-8-1)x^2 + (\dfrac{32}{3} + \dfrac{1}{2}+8)x^4 + ...) }

\mathtt{ e^{-x^2} cos (4x) = ( 1 -9x^2 + (\dfrac{64+3+48}{6})x^4+ ...) }

\mathtt{ e^{-x^2} cos (4x) = ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }

Finally , multiplying 5 with \mathtt{ e^{-x^2} cos (4x) } ; we have:

The first three nonzero terms in the Maclaurin series is

\mathbf{ 5e^{-x^2} cos (4x)  }= \mathbf{ 5 ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }

7 0
3 years ago
Other questions:
  • How many times longer is the length of the rectangle compared to the width? 14.4cm by 1.6cm
    10·1 answer
  • Logan is studying the reproductive rate of fruit flies and uses the table below to record the fruit fly population every week fo
    6·1 answer
  • (5 pt) Which question is being asked in this story problem? Dorothy has a stamp collection. She bought 300 stamps and some pages
    9·1 answer
  • Use a transformation to solve the equation. w/4 = 8 can you also leave a detailed explanation on how this equation = 32
    9·1 answer
  • What are the steps to get 4 - 2i?
    10·1 answer
  • What is the simplified form of the expression? 9. (m^7)^2 a) 2m^14 b) m^49 c) m^9 d) m^14
    8·1 answer
  • What are the values of the regrouped amounts in the multiplication 435 times 17
    9·1 answer
  • What is -1/2 - (-4/5)?
    10·2 answers
  • Consider the points plotted on the number line shown.
    9·2 answers
  • 1 point<br>What is the perimeter of the compound figure below?<br>6 m<br>7 m<br>4 m<br>12 m​
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!