Answer:

Step-by-step explanation:
Write a function whose k(x) values are 5 more than four times the principal square root of x.
So,
the principal square root of x 
four times the principal square root of x 
5 more than four times the principal square root of x 
Thus,

Answer:
x = 7
Step by step explanation:
<em>minus</em><em> </em><em>x</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em>
6 = x -1
<em>add</em><em> </em><em>1</em><em> </em><em>on</em><em> </em><em>both</em><em> </em><em>sides</em>
<em>x</em><em> </em><em>=</em><em> </em><em>7</em>
The cone equation gives

which means that the intersection of the cone and sphere occurs at

i.e. along the vertical cylinder of radius

when

.
We can parameterize the spherical cap in spherical coordinates by

where

and

, which follows from the fact that the radius of the sphere is 3 and the height at which the sphere and cone intersect is

. So the angle between the vertical line through the origin and any line through the origin normal to the sphere along the cone's surface is

Now the surface area of the cap is given by the surface integral,




Answer:
use ur brain
Step-by-step explanation:
ask ur teacher if the be bad teacher google it