I need the answer ASAP

At the end of the year, Mrs. Weeks bought an assortment of new balls to replace some of the old ones. She had $150.00 to spend.

Igoryamba

Answer:

Wait how much is the ball cost

Step-by-step explanation: Well if mrs. weeks buyed 2 balls for $150 then the balls cost $75. or if she have different kind of balls it can be $25 each and she bought 3 balls each kind.

3 0

4 years ago

You start 80 miles east of pittsburgh and drive east at a constant speed of 65 miles per hour. (assume that the road is straight

Masja [62]

We get 65 miles away from Pittsburgh each hour, but we also started 80 miles away. Thus, our formula for dd is dd = 65tt + 80

7 0

3 years ago

What does n^9/n^5 equal

vovangra [49]

Answer:

$n^4$

Step-by-step explanation:

Rule:

$\dfrac{a^m}{a^n} = a^{m - n}$

Your problem:

$\dfrac{n^9}{n^5} = n^{9 - 5} = n^4$

4 0

4 years ago

When 3010 adults were surveyed in a poll, 27% said that they use the Internet. Is it okay for a newspaper reporter to write th

tamaranim1 [39]

Answer:

Null hypothesis: $p=0.25$

Alternative hypothesis: $p \neq 0.25$

z=2.53

pv=0.0114

So based on the p value obtained and using the significance given $\alpha=0.05$ we have $p_v$ so we can conclude that we reject the null hypothesis, and we can said that at 5% of significance the proportion of people who says that they use the Internet differs from 0.25 or 25% .

Step-by-step explanation:

1) Data given and notation

n=3010 represent the random sample taken

X represent the people who says that said that they use the Internet.

$\hat p=\frac{X}{106}=0.27$ estimated proportion of people who says that said that they use the Internet.

$p_o=0.25$ is the value that we want to test

$\alpha$ represent the significance level

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

2) Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that 50% of people who says that they would watch one of the television shows.:

Null hypothesis: $p=0.25$

Alternative hypothesis: $p \neq 0.25$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

3) Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.27 -0.25}{\sqrt{\frac{0.25(1-0.25)}{3010}}}=2.53$

4) Statistical decision

P value method or p value approach . "This method consists on determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

We have the significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a bilateral test the p value would be:

$p_v =2*P(z>2.53)=2*(0.0057)=0.0114$

So based on the p value obtained and using the significance given $\alpha=0.05$ we have $p_v$ so we can conclude that we reject the null hypothesis, and we can said that at 5% of significance the proportion of people who says that they use the Internet differs from 0.25 or 25% .

3 0

3 years ago

Someone tell me answer!!!

sergij07 [2.7K]

Answer:

X=70

Step-by-step explanation:

180-120=60

60 + 50=110

180-110=70

3 0

3 years ago

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