Answer: The distance between the points (-6,7) and (-1,-5) is 13 units.
Solution:
P1=(-6,7)=(x1,y1)→x1=-6, y1=7
P2=(-1,-5)=(x2,y2)→x2=-1,y2=-5
Distance between points P1 and P2: d=?
d=sqrt [ (x2-x1)^2 + (y2-y1)^2 ]
Replacing the knwon values:
d=sqrt [ (-1-(-6))^2 + (-5-7)^2 ]
d=sqrt [ (-1+6)^2 + (-12)^2 ]
d=sqrt [ (5)^2 + 144 ]
d=sqrt [ 25 + 144 ]
d=sqrt [ 169 ]
d=13
Hey there! I'm happy to help!
Since we are using graphs, we will do not need to algebraically solve this system of equations.
When you graph a system of equations, the solution is always the point at which the two lines intersect.
Here is our system of equations graphed. We see that the lines intersect at about (1 1/3, 2 1/3). Therefore, the correct answer is C. x=1 1/3, y=2 1/3
Have a wonderful day! :D
Answer:
Read explanation and apply it
Step-by-step explanation:
The vertex form of a quadratic equation is 
The general form of a quadratic equation is 
The factored form of a quadratic equation is 
The one which reveals the zeros of f(x) without needing to alter the equation is the factored form
.
When f(x)=0, we have 
The values of x are
and
.
I hope this guides you to choose the correct answer.
Answer:
See Explanation
Step-by-step explanation:
You are doing simple math within the square root. For instance where x=-2 you substitute -2 for x then add 2 which gives you 0 leaving you with -6.
for x=2 you end up with "square root 2+2" which gives you 4 and the square root of 4 is 2 so you add -6 to 2 giving you the answer of -4.
Answer:
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Step-by-step explanation:
:)