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3 years ago

What is the equation of the line that is perpendicular to the given line and has an x-intercept of -3?

Mathematics

1 answer:

Anvisha [2.4K]3 years ago

3 0

Answer:

$y=-\frac{3}{2}x-\frac{9}{2}$

Step-by-step explanation:

Let the equation of the perpendicular line is,

y = mx + b

where m = slope of the line

b = y-intercept

From the graph, slope of the line passing through (0, -1) and (3, 1),

m' = $\frac{y_2-y_1}{x_2-x_1}$

m' = $\frac{1+1}{3-0}$

m' = $\frac{2}{3}$

To get the slope (m) of this line we will use the property of perpendicular lines,

m × m' = (-1)

m × $\frac{2}{3}$ = -1

m = $-\frac{3}{2}$

Equation of the perpendicular line will be,

$y=-\frac{3}{2}x+b$

x-intercept of the line is (-3) therefore, point on the line is (-3, 0)

0 = $-\frac{3}{2}(-3)+b$

b = $-\frac{9}{2}=-4.5$

Equation of the line will be,

$y=-\frac{3}{2}x-\frac{9}{2}$

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This means that the correct answer to your question is option A.
Let me know if you have any further questions.
:)

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