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3 years ago

Can someone please help me with this pleaseeeee

Computers and Technology

1 answer:

vladimir1956 [14]3 years ago

6 0

Answer:

The answer of this question is given below into explanation section

Explanation:

answer (a)

I visited the carrerbuilder dot com and search for data entry job. The link of the posting is given below

https://www.careerbuilder.com/jobs?utf8=%E2%9C%93&keywords=data+entry&location=

answer(B)-Requirements of the the job

Previous office experience (data entry experience a plus)
Proficient with a computer and computer software (Excel knowledge required)
Excellent verbal and written communication skills
The ability to multi-task and work in a team-oriented environment
High School Diploma / G.E.D.
Ability to meet background check and drug screening requirements

answer(C)-Tasks of the job

Open, sort, and scan documents
Track all incoming supplies and samples
Data entry of samples that come in
Assist with documentation and maintaining of data
Prepare and label information for processing
Review and correct any data entry error or missing information

answer (d)

I have 3 years of experience in organization administration where I managed the organization data, generated reports and communicated verbally and written within the organization efficiently.

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Compare the current in two lightbulbs wired in a series circuit

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3 years ago

7.8.1: Function pass by reference: Transforming coordinates. Define a function CoordTransform() that transforms the function's f

Lilit [14]

Answer:

Here is the CoordTransform() function:

void CoordTransform(int xVal, int yVal, int &xValNew, int &yValNew){

xValNew = (xVal + 1) * 2;

yValNew = (yVal + 1) * 2; }

The above method has four parameters xVal and yVal that are used as input parameters and xValNew yValNew as output parameters. This function returns void and transforms its first two input parameters xVal and yVal into two output parameters xValNew and yValNew according to the formula: new = (old + 1) *

Here new variables are xValNew and yValNew and old is represented by xVal and yVal.

Here the variables xValNew and yValNew are passed by reference which means any change made to these variables will be reflected in main(). Whereas variables xVal and yVal are passed by value.

Explanation:

Here is the complete program:

#include <iostream>

using namespace std;

void CoordTransform(int xVal, int yVal, int &xValNew, int &yValNew){

xValNew = (xVal + 1) * 2;

yValNew = (yVal + 1) * 2;}

int main()

{ int xValNew;

int yValNew;

int xValUser;

int yValUser;

cin >> xValUser;

cin >> yValUser;

CoordTransform(xValUser, yValUser, xValNew, yValNew);

cout << "(" << xValUser << ", " << yValUser << ") becomes (" << xValNew << ", " << yValNew << ")" << endl;

return 0; }

The output is given in the attached screenshot

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2 years ago

A laptop gets replaced if there's a hardware issue. Which stage of the hardware lifecycle does this scenario belong to?

Ilya [14]

Answer: Maintenance. This is the stage where software is updated and hardware issues are fixed if and when they occur. Retirement. In this final stage, hardware becomes unusable or no longer needed and it needs to be properly removed from the fleet

Explanation:

3 0

3 years ago

Write a method transpose, that takes as argument a 2D array of integers, myTable, and returns the transpose of myTable. The tran

Gelneren [198K]

Answer:

The program to this question can be given as:

Program:

import java.util.*; //import package

public class Main //defining class

{

public static int[][] transpose(int[][] a1) //defining function transpose

{

int i,j; //define variables

int[][] transpose = new int[a1[0].length][a1.length]; //define variable transpose.

//loop for transpose matrix.

for(i = 0; i < a1.length; i++)

{

for(j = 0; j < a1[i].length; j++)

{

transpose [j][i] = a1[i][j]; //hold value in transpose variable

}

return transpose ; //return transpose matrix.

}

public static void main(String[] args) //main method.

{

int row,col,i,j; //defining variable.

Scanner obj = new Scanner(System.in); //creating Scanner class Object

System.out.print("Enter number of rows: ");//message

row = obj.nextInt(); //input rows form user.

System.out.print("Enter number of columns: ");//message

col = obj.nextInt(); //input columns form user.

int[][] a1 = new int[row][col]; //defining array.

System.out.println("Enter matrix"); //message

// loop for input array elements from user

for(i=0; i<a1.length;i++)

{

for(j=0; j<a1[i].length;j++)

{

a1[i][j]=obj.nextInt(); //input in array variable.

}

System.out.println("Matrix you insert :"); //message

// loop for display array.

for(i=0; i<a1.length;i++)

{

for(j=0; j<a1[i].length;j++)

{

System.out.print(a1[i][j]+" "); //print matrix

}

System.out.print("\n");

}

int[][] result = transpose(a1); //define result array variable that holds function value.

System.out.println("Transposed matrix is :");

//use loop for print Transpose matrix.

for(i = 0;i < result.length;i++)

{

for (j = 0; j < result[i].length;j++)

{

System.out.print(result[i][j] + " "); //print matrix

}

System.out.print("\n");

}

Output:

Enter number of rows: 2

Enter number of columns: 3

Enter matrix

Matrix you insert :

2 3 4

9 8 7

Transposed matrix is :

2 9

3 8

4 7

Explanation:

The description of the above program can be given as:

In the above program firstly import a package, then declare a class that is "Main" inside a class defining a transpose() function this function returns a matrix in transpose form.
In the main class, we define a variable and matrix that is "row, col, i, j and a1[][]". Then we Creating a scanner class object, which is used by row, col and a1[][] variables for user input.
The row and col variables are used to declare matrix size and i, j variable is used in the loop for insert and display matrix.
a1[][] matrix is used for input matrix elements and passes into transpose() function as an argument that returns a value that is held in the result variable. This is used as a loop for the print transpose matrix.

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3 years ago

You have one ip address provided from your isp with a /30 mask. However, you have 300 users that need to access the internet. Wh

creativ13 [48]

Answer:

a. PAT

Explanation:

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2 years ago