Answer:
29 L
Explanation:
Please see the step-by-step solution in the picture attached below.
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Name for the compound HF is Hydrogen fluoride.
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Answer:
C) the double bond results in the bypassing of the first oxidation step of the pathway, thereby eliminating one FADH2 product
Explanation:
The beta oxidation of fatty acids is the process by which long chain saturated and unsaturated fatty acids are oxidized to the two-carbon product, acetylCoA.
The beta oxudation of fatty acids occurs in four steps after which the chain length is shortened by 2 with cleavage of an acetylCoA molecule.
The first step involves the oxidation of the fatty acid with introduction of a double bond between C-2 and C-3 of the long carbon chain. This reaction produces FADH2 which donates its electrons to electron carriers in the electron transport chain tomproduce 1.5 moles of ATP. This is the case with saturated fatty acids.
However, in unsaturated fatty acids (which are less reduced than saturated fatty acids) where there is already a double bond innthe molecule, the double bond results in the bypassing of the first oxidation step of the pathway, thereby eliminating one FADH2 product.
This causes a reduction In the number of ATP produced by unsaturated fatty acids when compared to saturated fatty acids.
Answer:
The element that is commonly used to reduce iron oxide would be <u>carbon.</u>
Explanation:
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Answer:
Only Mn⁺² is present.
Explanation:
- When an aqueous solution of NaCl is added, the Cl⁻ species is introduced. In the presence of Cl⁻, Hg₂²⁺ would precipitate as Hg₂Cl₂.
- When an aqueous solution of Na₂SO₄ is added, the SO₄⁻² species is introduced. In the presence of SO₄⁻², Ba⁺² would precipitate as BaSO₄.
No precipitate formed when either of these solutions were added, thus <u>the sample does not contain Hg₂⁺² nor Ba⁺²</u>.
- Under basic conditions Mn⁺² would precipitate as Mn(OH)₂. A precipitate formed once the solution was made basic, so <u>the sample contains Mn⁺²</u>.
