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ratelena [41]
3 years ago
10

A container initially holds 1.24mol of hydrogen gas and has a volume of 27.8L. Hydrogen gas was added to the container, and the

final volume increased to 40.6L while the temperature and pressure remained constant. How many moles of hydrogen gas are in the container?
Chemistry
1 answer:
Fantom [35]3 years ago
3 0

Answer:

After increasing the volume, we have 1.81 moles of hydrogen gas in the container

Explanation:

Step 1: Data given

Number of moles hydrogen gas (H2) = 1.24 moles

Volume of hydrogen gas (H2° = 27.8 L

The final volume is increas to 40.6 L

Step 2: Calculate the new number of moles

V1/n1 = V2/n2

⇒with V1 = the initial volume = 27.8 L

⇒with n1 = the initial number of moles H2 = 1.24 moles

⇒with V2 = the final volume = 40.6 L

⇒with n2 = the new number of moles = TO BE DETERMINED

27.8L / 1.24 moles = 40.6 L / n2

n2 = 40.6 / (27.8/1.24)

n2= 1.81 moles

After increasing the volume, we have 1.81 moles of hydrogen gas in the container

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A weather balloon is filled with helium that occupies a volume of 5.37 104 L at 0.995 atm and 32.0°C. After it is released, it r
svp [43]

Answer:

The new volume is 63583 L

Explanation:

Step 1: Data given

The initial volume of the balloon = 5.37 * 10^4 L

The initial pressure = 0.995 atm

The initial temperature = 32.0 °C = 305.15 K

The pressure decreased to 0.720 atm

The temperature decreased to -11.7 °C = 261.45 K

Step 2: Calculate the new volume

P1*V1 / T1 = P2*V2/T2

⇒with P1 = the initial pressure = 0.995 atm

⇒with V1 = the initial volume = 5.37 *10^4 L

⇒with T1 = the initial temperature = 305.15 K

⇒with P2 = the decreased pressure = 0.720 atm

⇒with V2 = the new volume = TO BE DETERMINED

⇒with T2 = the decreased temperature : 261.45 K

(0.995 * 5.37*10^4)/305.15 = (0.720 * V2) / 261.45

V2 = 63583 L

The new volume is 63583 L

8 0
3 years ago
Which will have the lowest boiling point?
In-s [12.5K]

Some of the solutions exhibit colligative properties. These properties depend on the amount of

solute dissolved in a solvent. These properties include freezing point depression, boiling

point elevation, osmotic pressure and vapor pressure lowering. From the given choices, the correct answer is the first option. Pure water will have the lowest boiling point because there are no solute particles to change the boiling point of water while other options will have an elevated boiling point because of the solute.

Read more on Brainly.com - brainly.com/question/1437052#readmore

8 0
3 years ago
Read 2 more answers
The molar solubility of zns is 1.6 Ã 10-12 m in pure water. Calculate the ksp for zns.
Oksi-84 [34.3K]

Answer:

The solubility product of zinc sulfide is 2.56\times 10^{-24}.

Explanation:

Solubility of the zinc sulfide = S=1.6\times 10^{-12}

ZnS\rightleftharpoons Zn^{2+}+S^{2-}

                S        S

The expression of solubility product is given by :

K_{sp}=[Zn^{2+}]\times [S^{2-}]

K_{sp}=S\times S=S^2

=1.6\times 10^{-12}\times 1.6\times 10^{-12}=2.56\times 10^{-24}

The solubility product of zinc sulfide is 2.56\times 10^{-24}.

5 0
3 years ago
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