What is the uppermost, horizontal area of a page?

What is the sum of 6 and it’s additive inverse

weeeeeb [17]

The additive inverse of 6 is -6.

8 0

3 years ago

The water-gas shift reaction plays a central role in the chemical methods for obtaining cleaner fuels from coal: CO(g) + H2O(g)

taurus [48]

<u>Answer:</u> The concentration of carbon dioxide, hydrogen gas, carbon monoxide and water when equilibrium is re-established are 0.362 M, 0.212 M, 0.138 M and 0.138 M respectively.

<u>Explanation:</u>

For the given chemical reaction:

$CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)$

The expression of $K_c$ for above reaction follows:

$K_c=\frac{[CO_2][H_2]}{[CO][H_2O]}$ ........(1)

We are given:

$[CO]_{eq}=[H_2O]_{eq}=[H_2]_{eq}=0.10M$

$[CO_2]_{eq}=0.40M$

Putting values in above equation, we get:

$K_c=\frac{0.40\times 0.10}{010\times 0.10}\\\\K_c=4$

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Moles of hydrogen gas = 0.30 mol

Volume of solution = 2.0 L

Putting values in above equation, we get:

$\text{Molarity of }H_2=\frac{0.30mol}{2L}=0.15M$

When hydrogen gas is added, the concentration of product gets increased. But, by Le-Chatelier's principle, the equilibrium will shift in the direction where concentration of product must decrease, which is in the backward direction.

Concentration of hydrogen gas when equilibrium is re-established = 0.1 + 0.15 = 0.25 M

Now, the equilibrium is shifting to the reactant side. The equation follows:

$CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)$

Initial: 0.1 0.1 0.4 0.1

At eqllm: 0.1+x 0.1+x 0.4-x 0.25-x

Putting values in expression 1, we get:

$4=\frac{(0.25-x)(0.4-x)}{(0.1+x)(0.1+x)}\\\\3x^2+1.45x-0.06=0\\\\x=0.038,-0.522$

Neglecting the negative value of 'x'

Calculating the concentrations of the species:

Concentration of carbon dioxide = (0.4 - x) = (0.4 - 0.038) = 0.362 M

Concentration of hydrogen gas = (0.25 - x) = (0.25 - 0.038) = 0.212 M

Concentration of carbon monoxide = (0.1 + x) = (0.1 + 0.038) = 0.138 M

Concentration of water = (0.1 + x) = (0.1 + 0.038) = 0.138 M

Hence, the concentration of carbon dioxide, hydrogen gas, carbon monoxide and water when equilibrium is re-established are 0.362 M, 0.212 M, 0.138 M and 0.138 M respectively.

8 0

3 years ago

3. Concentric circles (one smaller circle inside another). As

Agata [3.3K]

Answer:

Bohr's "planetary project" was widely accepted because he was able to explain a factor that Ruthford failed to achieve. Bohr was able to explain how electrons and energy worked in a simple atom, such as hydrogen, which consists of an electron orbiting a single proton.

In addition, he was able to explain, using the principles of gravity, how electrons do not fall on top of the proton but rather orbit around the proton.

Explanation:

Danish physicist Niels Bohr proposed an atomic model for the hydrogen atom which was later extended to other elements. Its model is based on the Solar System, in which the planets rotate around the sun. For Bohr, electrons rotate in orbit around the atomic nucleus grouped into energy levels.

Until 1913, there was no satisfactory model that explained even the simplest of atoms - hydrogen, which consists of an electron orbiting a single proton.

By assigning the concept of energy levels, Bohr was able to create a version of the hydrogen atom that was possibly stable and satisfying spectral observations. Until then, all theoretical predictions suggested that it should not exist for more than a split second - a failure that bothered physicists a great deal. It was therefore a monumental advance.

Bohr was also able to explain why electrons do not fall on protons using concepts of gravity. In Bohr's atomic model, electrons rotate around the nucleus like planets around the sun. According to Bohr, an electron does not fall into the nucleus because it cannot: its orbits are like steps in a ladder. We may be in one or the other but not in two. Imagine the atom as a kind of tiny football stadium.

The core is in the center of the lawn. Electrons can run around the steps of the stands. From time to time, they jump from step to step. If they go up they use energy, down they release energy.

However, electrons can never leave the stands to invade the field. Bohr did not explain why the ban.

8 0

3 years ago

The reaction of Cr2O3 with silicon metal at high temperatures will make chromium metal. 2CrO3(s) + 3Si(s)----> 4Cr(l) + 3SiO2

nalin [4]

Answer: 51.45 grams of excess reagent is left after the completion of reaction.

Explanation: For the calculation of moles, we use the formula:

$Moles=\frac{\text{Given mass}}{\text{Molar mass}}$ ....(1)

For Si

Given mass = 92 grams

Molar mass = 28g/mol

Putting values in equation 1, we get:

$Moles=\frac{92g}{28g/mol}=3.285moles$

For $Cr_2O_3$

Given mass = 112 grams

Molar mass = 116g/mol

Putting values in equation 1, we get:

$Moles=\frac{112g}{116g/mol}=0.965moles$

The reaction follows:

$2Cr_2O_3(s)+3Si(s)\rightarrow 4Cr(l)+3SiO_2(s)$

By Stoichiometry,

2 moles of $Cr_2O_3$ reacts with 3 moles of silicon

So, 0.965 moles of $Cr_2O_3$ reacts with = $\frac{3}{2}\times 0.965$ = 1.4475 moles of Silicon.

As, the moles of silicon is more than the required amount and is present in excess.

So, the excess reagent for the reaction is Silicon.

Moles of silicon remained after reaction = 3.285 - 1.4475 = 1.8375 moles

To calculate the amount of Silicon left in excess is calculated by using equation 1:

$1.8375=\frac{\text{Given mass}}{28}$

Amount of Silicon in excess will be 51.45 grams.

5 0

4 years ago

What is the mass of 3.5 l of co2(g)? (density = 0.0019 g/ml, answer to hundredths place)?

monitta

Density is defined as mass per unit volume.
$density = \frac{mass}{volume}$
the mass of 1 mL of CO₂ is - 0.0019 g
3.5 L = 3500 mL
then the mass of 3500 mL of CO₂ is - 0.0019 g/mL x 3500 mL = 6.65 g
mass of 3.5 L of CO₂ is 6.65 g

4 0

4 years ago

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