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3 years ago

The study of the Earth's magnetic field is known as

Physics

1 answer:

marissa [1.9K]3 years ago

5 0

The study of the Earth's magnetic field is known as: B. paleomagnetism

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Find the mass of a football player who's momentum is 630 kg•m/s backward and. is traveling at 7 m/s.

Setler [38]

Answer:

<h2>The answer is 90 kg</h2>

Explanation:

In order to find the mass of the football we use the formula

$m = \frac{p}{v} \\$

where

p is the momentum

v is the velocity

We have

$m = \frac{630}{7} \\$

We have the final answer as

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3 years ago

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Compose a paragraph that identifies and describes each of the three Siberian regions.

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3 years ago

An what would be needed to change an objects state of motion

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Inertia: tendency of an object to resist changes in its velocity. An object at rest has zero velocity - and (in the absence of an unbalanced force) will remain with a zero velocity. Such an object will not change its state of motion (i.e., velocity) unless acted upon by an unbalanced force.

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4 years ago

Explain the difference between a fuse and a circuit breaker. If you were designing a circuit for a reading lamp, would you inclu

sesenic [268]

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3 years ago

The outer layer of cable on a cable reel is 16.2 cm from the center of the reel. The reel is initially stationary and can rotate

ahrayia [7]

Answer:

B. w=12.68rad/s

C. α=3.52rad/s^2

Explanation:

We can solve this problem by taking into account that (as in the uniformly accelerated motion)

$\theta=\omega_{0}t+\frac{1}{2}\alpha t^{2}\\\theta = \frac{s}{r}$ ( 1 )

where w0 is the initial angular speed, α is the angular acceleration, s is the arc length and r is the radius.

In this case s=3.7m, r=16.2cm=0.162m, t=3.6s and w0=0. Hence, by using the equations (1) we have

$\theta=\frac{3.7m}{0.162m}=22.83rad$

$22.83rad=\frac{1}{2}\alpha (3.6s)^2\\\\\alpha=2\frac{(22.83rad)}{3.6^2s}=3.52\frac{rad}{s^2}$

to calculate the angular speed w we can use $\alpha=\frac{\omega _{f}-\omega _{i}}{t _{f}-t _{i}}\\\\\omega_{f}=\alpha t_{f}=(3.52\frac{rad}{s^2})(3.6)=12.68\frac{rad}{s}$

Thus, wf=12.68rad/s

C) We can use our result in B)

$\alpha=3.52\frac{rad}{s^2}$

I hope this is useful for you

regards

3 0

3 years ago

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