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Galina-37 [17]
3 years ago
9

Consider a coin which is tossed straight up into the air. After it is released it moves upward, reaches its highest point and fa

lls back down again. Air resistance can be neglected. What force acts on the coin while it moves upward after it is released
Physics
1 answer:
avanturin [10]3 years ago
3 0

Answer:

GRAVITATIONAL FORCE

Explanation:

We may have noticed that a body thrown upward in air falls back down again after attaining a particular height. The object was able to fall down back due to the effect of gravity acting on it. If there are no force of gravity acting on the body, the body will not fall back but rather disappears into the thin air.

A coin tossed upward in the air which falls back down when released is therefore under the influence of gravity i.e GRAVITATIONAL FORCE while it moves upward after it is released

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pakka acquires a velocity of 72 km per hour in 10 seconds starting from rest find a ) the acceleration b)the average velocity c)
nadezda [96]
Acceleration equals 24 km/s
Average equals 396km/s
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4 years ago
-Para lograr que una pieza de 0,300 kg de cierto metal aumente su temperatura desde 40°C a 60 °C ha sido necesario suministrarle
marishachu [46]

Answer:

parte a) el calor específico es c = 0.383 J /(gr*K)

parte b) la temperatura inicial es T inicial= 52.72 °C

Explanation:

para el primer punto la formula para el calor Q es:

Q = m * c * ( T final - T inicial )

donde

m= masa de la pieza = 0.300 kg = 300 gr

Q = flujo de energía en forma de calor= 2299 J

c = calor específico

T final = temperatura final =40°C

T inicial = temperatura inicial = 60 °C

entonces

Q = m * c * ( T final - T inicial )

c = Q / [ m* ( T final - T inicial ) = 2299 J/[ 300 gr  * ( 60 °C - 40°C )]

= 0.383 J /(gr*K)

c = 0.383 J /(gr*K)

para el segundo punto usamos la misma formula

Q = m * c * ( T final - T inicial )

pero

m= 200 gr= 0.200 kg

c=459.8 J/(kg*K) , Q =20.900 J , T final = 280 °C

Q = m * c * ( T final - T inicial )

T inicial = T final - Q/(m*c)  =280 °C - 20.900 J/(459.8 J/(kg*K)* 0.200 kg) = 52.72 °C

7 0
4 years ago
A wire is stretched just to its breaking point by a force F . A longer wire made of the same material has the same diameter. The
ICE Princess25 [194]

Answer: No

Explanation:

The force F required is equal to the Force exerted in stretching the first material since conditions are the same

8 0
3 years ago
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A person walks first at a constant speed of 5.00 m.s-1
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The average speed of the person over the entire trip is 3.75 m/s.

<h3>Average speed of the person</h3>

Average speed = total distance/total time

Average speed = (d + d)/(d/Va + d/Vb)

where;

  • d is the distance in a single trip
  • Va is speed from point A
  • Vb is the speed from point B

Average speed = (2Vavb)/(Va + Vb)

Average speed = (2 x 5 x 3)/(5 + 3)

Average speed = 3.75 m/s

Thus, the average speed of the person over the entire trip is 3.75 m/s.

Learn more about average speed here: brainly.com/question/6504879

#SPJ1

4 0
2 years ago
8. A 20 newton object is pulled along a surface at a constant speed of 3.0 meters per second using a force of 4.5 newtons. The k
tia_tia [17]

To calculate the kinetic coefficient of friction is closest to: 1. 0.23.

<u>Given the following data:</u>

  • Horizontal force = 4.5 Newton
  • Normal force = 20 Newton
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To calculate the kinetic coefficient of friction:

Mathematically, the kinetic force is given by this formula;

F_k = uF_n

<u>Where;</u>

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Making μ the subject of formula, we have:

u=\frac{F_k}{F_n}

Substituting the given parameters into the formula, we have;

u=\frac{4.5}{20}

u = 0.225 ≈ 0.23

Read more on kinetic coefficient of friction here: brainly.com/question/13940648

6 0
3 years ago
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