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3 years ago

What is the relationship between height and gravitational potential energy of water behind a dam?

Physics

1 answer:

Andrews [41]3 years ago

7 0

Answer:

3. $h^2$

Explanation:

Energy of volume contained in a dam is given by

$E=\dfrac{1}{2}A\rho gh^2$

where,

A = Horizontal surface area of the barrage

$\rho$ = Density of water

g = Acceleration due to gravity = 9.81 m/s²

h = Vertical tidal range,

It can be seen that

$E\propto h^2$

Hence, the energy is proportional to $h^2$

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The process by which you group things based on their similarities is known as classifying.

dusya [7]

True. Classifying by similarities is the basis for biological classification.

8 0

3 years ago

When two ions form a bond, the overall charge of that compound will ALWAYS become..

Maslowich

Answer:

C. Neutral

Explanation:

Ions will combine in a way that the overall ionic compound will always be neutral.

8 0

3 years ago

Master of physics needed

Delicious77 [7]

Hey JayDilla, I get 1/3. Here's how:
Kinetic energy due to linear motion is:
$E_{linear}= \frac{1}{2}mv^2$
where
$v=r \omega$
giving
$E_{linear}= \frac{1}{2}mr^2 \omega ^2$

The rotational part requires the moment of inertia of a solid cylinder
$I_{cyl} = \frac{1}{2}mr^2$
Then the rotational kinetic energy is
$E_{rot}= \frac{1}{2}I \omega ^2= \frac{1}{4}mr^2 \omega ^2$
Adding the two types of energy and factoring out common terms gives
$\frac{1}{2}mr^2 \omega ^2(1+ \frac{1}{2})$
Here the "1" in the parenthesis is due to linear motion and the "1/2" is due to the rotational part. Since this gives a total of 3/2 altogether, and the rotational part is due to a third of this (1/2), I say it's 1/3.

8 0

4 years ago

A uniformly charged sphere has a total charge of 300uc and a radius of 8cm. Find the electric field density at A point 16cm from

s2008m [1.1K]

E = kQ 

(r + h)²

where,

k = 9 × 10^9Nm²C^-2

Q = total charge, 300uC = 300 × 10^ -6C

r = 8 × 10^ -2m

h = 16 × 10^ -2m

then,

E = 9e9 * 300e^-6 

(8e^-2 + 16e^-2)²

E = 4687500N/C

6 0

3 years ago

A car traveling with an initial velocity of 12 m/s accelerates at a constant rate of 2.2 m/s2 for a time of 4 seconds.

bazaltina [42]

So what's the question?

4 0

3 years ago