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svp [43]
3 years ago
13

Calculate the mean of the data set below. (Round to the nearest hundredth.)

Mathematics
1 answer:
ruslelena [56]3 years ago
5 0
If it is the question I just completed it should be A. 76.4
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1) Last Tuesday, Regal Cinemas sold a total of 85 movie tickets. Ticket sales totaled
irakobra [83]

In this question, some of the data is missing so its a complete question and the solution can be defined as follows:

\bold{\text{m = matinee tickets}} \\\\\bold{\text{s = student tickets}}\\\\\bold{\text{r = regular tickets}}

By given question, calculating equations are:

\to \bold{m + s + r = 8500}............................................(a)\\\\\to \bold{5m + 6s + 8.50r = 64600}............................(b)\\\\\to \bold{s = 2m}...................(c)

Putting the equation (c) value in the equation (a) to calculate value:

m + 2m + r = 8500\\\\3m + r = 8500\\\\r = 8500 - 3m........................................(d)

Putting equation (c) and (d) value into equation (b):

5m + 6(2m) + 8.50(8500 - 3m) = 64600\\\\5m + 12m + 72250 - 25.50m = 64600\\\\-8.50m = 64600 - 72250 \\\\-8.50m = -7650\\\\m = \frac{-7650}{-8.50}\\\\m = \frac{7650}{8.50}\\\\m = 900

Putting m value into equation (c) and equation (d) to calculate its value:

Calculating the s value:

\to s = 2(900) \\\\ \to s = 1800

Calculating the r value:

\to r = 8500 - 3(900) \\\\\to r = 8500 - 2700\\\\\to r = 5800\\\\

So, the final value of "m, s, and r" are "900, 1800, and 5800".

Learn more:

brainly.com/question/2929577

7 0
3 years ago
HELP ME FOR NUMBER 1 THROUGH 8 QUICKLY
Slav-nsk [51]
I did this last semester and I would remember it but unfortunately this was the only section I didn't study for the final bc we did one day on it. I'm sorry. Good luck.
6 0
3 years ago
Can someone pls graph the picture below.
grin007 [14]

Answer:

  see below

Step-by-step explanation:

This graphs as 3 horizontal lines. The open circles are at the ends of the interval where the function is undefined or is defined as a different value.

3 0
3 years ago
Consider the following division of polynomials.
Bond [772]

x^4=x^2\cdot x^2. Multiplying the denominator by x^2 gives

x^2(x^2+2x+8)=x^4+2x^3+8x^2

Subtracting this from the numerator gives a remainder of

(x^4+x^3+7x^2-6x+8)-(x^4+2x^3+8x^2)=-x^3-x^2-6x+8

-x^3=-x\cdot x^2. Multiplying the denominator by -x gives

-x(x^2+2x+8)=-x^3-2x^2-8x

and subtracting this from the previous remainder gives a new remainder of

(-x^3-x^2-6x+8)-(-x^3-2x^2-8x)=x^2+2x+8

This last remainder is exactly the same as the denominator, so x^2+2x+8 divides through it exactly and leaves us with 1.

What we showed here is that

\dfrac{x^4+x^3+7x^2-6x+8}{x^2+2x+8}=x^2-\dfrac{x^3+x^2+6x-8}{x^2+2x+8}

=x^2-x+\dfrac{x^2+2x+8}{x^2+2x+8}

=x^2-x+1

and this last expression is the quotient.

To verify this solution, we can simply multiply this by the original denominator:

(x^2+2x+8)(x^2-x+1)=x^2(x^2-x+1)+2x(x^2-x+1)+8(x^2-x+1)

=(x^4-x^3+x^2)+(2x^3-2x^2+2x)+(8x^2-8x+8)

=x^4+x^3+7x^2-6x+8

which matches the original numerator.

3 0
3 years ago
Read 2 more answers
Jacks family bought five concert tickets for $250 what was the price per ticket?
Mashcka [7]

answer : 0.02

$250 ÷ 5 = 0.02

5 0
2 years ago
Read 2 more answers
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