Answer:
the mass of CaO present at equilibrium is, 0.01652g
Explanation:
= 3.8×10⁻²
Now we have to calculate the moles of CO₂
Using ideal gas equation,
PV =nRT
P = pressure of gas = 3.8×10⁻²
T = temperature of gas = 1000 K
V = volume of gas = 0.638 L
n = number of moles of gas = ?
R = gas constant = 0.0821 L.atm/mole.k

Now we have to calculate the mass of CaO
mass = 2.95 * 10 ⁻⁴ × 56
= 0.01652g
Therefore,
the mass of CaO present at equilibrium is, 0.01652g
Answer:
The volume would be; 136.17 ml
Explanation:
Volume V1 = 150 mL
Temperature T1 = 20°C + 273 = 293 K
Pressure P1 = 758 - 17.54 = 740.46 torr
At STP;
Volume V2 = ?
Pressure P2 = 760 torr
Temperature T2 = 273 K
Using the general gas equation;
P1V1 / T1 = P2V2 / T2
Making V2 subject of formulae;
V2 = P1V1T2 / T1P2
Inserting the values we have;
V2 = 740.46 * 150 * 273 / 293 * 760
V2 = 136.17 ml
Answer:
26.981539 u
Atomic number: 13
Symbol: Al
Electron configuration: [Ne] 3s²3p¹
In an ionic bond, one atom essentially donates an electron to stabilize the other atom. The atoms in an ionic bond have different electronegativity values from each other.
While in a covalent bond, the atoms are bound by shared electrons and the electronegativity values are the same.