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Juli2301 [7.4K]
2 years ago
14

How do charged molecules pass through the membrane.

Chemistry
1 answer:
avanturin [10]2 years ago
6 0

Answer:

Through transport proteins

Explanation:

There's two transport proteins, channel/pore protein and carrier protein. Charged/polar molecules or ions need specific transport proteins to pass through across the plasma membrane. Transport proteins allows ions/polar molecules to bind to the specific site and allow them to pass through and enter the cell.

(btw, is this a chemistry question? isn't this a biology ques?)

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A scientist observed a 5-mL sample of an unknown substance. It is a blue liquid with a density of 1.2 g/cm. the substance reacts
LenaWriter [7]
Characteristic properties can be used to describe and identify the substances, while non-characteristic properties, although can be used to describe the substances, cannot be used to identify them.

Temperature, mass, color, shape and volume are examples of non-characteristic properties.

Density, boiling point, melting point, chemical reactivity are examples of characteristic properties.

List of the properties observed by the scientist:
-----------------------------------------------------------------
Property                                     Type of property
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Volume: 5 ml                              non-characteristic
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Color: blue                                 non-characteristic
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State: liquid                                characteristic
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density: 1.2 g/cm                        characteristic
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Reaction: reacts with CO2         characteristic
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5 0
3 years ago
What happens to a glass of water as the average molecular kinetic energy of the water molecules increases?
trasher [3.6K]
"The water becomes warmer."
<u>Remember</u>: Kinetic energy means how much, on average, a molecule is moving around. This is directly translated into heat. Therefore, the higher the kinetic energy, the more heat produced.
4 0
3 years ago
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Rank these real gases according to how closely they resemble an ideal gas. CO, N2, Ne, He, NH3
Gemiola [76]

He is the closest. Then:

Ne, N2, CO, NH3.

NH3 is the least closest to ideal.

8 0
3 years ago
The mass of sodium chloride in (g) is 14.19 The volume of ammonia solution in (mL) is 36.15 Calculate the following: What is the
Svetach [21]

This is an incomplete question, here is a complete question.

A weighed amount of sodium chloride is completely dissolved in a measured volume of 4.00 M ammonia solution at ice temperature, and carbon dioxide is bubbled in. Assume that sodium bicarbonate is formed util the limiting reagent is entirely used up. the solubility of sodium bicarbonate in water at ice temperature is 0.75 mol per liter. Also assume that all the sodium bicarbonate precipitated is collected and converted quantitatively to sodium carbonate.

Data to be used for calculating the results

-The mass of sodium chloride in (g) is 14.19

-The volume of ammonia solution in (mL) is 36.15

Calculate the following: What is the theoretical yield of sodium bicarbonate in grams?

Answer : The theoretical yield of sodium bicarbonate in grams is, 20.4 grams.

Explanation :

First we have to calculate the moles of NaCl and NH_3.

\text{ Moles of }NaCl=\frac{\text{ Mass of }NaCl}{\text{ Molar mass of }NaCl}=\frac{14.19g}{58.5g/mole}=0.243moles

\text{ Moles of }NH_3=\text{ Concentration of }NH_3\times \text{ Volume of solution}=4.00M\times 0.3615L=1.446moles

Now we have to calculate the limiting and excess reagent.

The balanced chemical reaction will be:

NH_3+NaCl+CO_2+H_2O\rightarrow NaHCO_3+NH_4Cl

From the balanced reaction we conclude that

As, 1 mole of NaCl react with 1 mole of NH_3

So, 0.243 mole of NaCl react with 0.243 mole of NH_3

From this we conclude that, NH_3 is an excess reagent because the given moles are greater than the required moles and NaCl is a limiting reagent and it limits the formation of product.

Now we have to calculate the moles of NaHCO_3

From the reaction, we conclude that

As, 1 mole of NaCl react to give 1 mole of NaHCO_3

So, 0.243 moles of NaCl react to give 0.243 moles of NaHCO_3

Now we have to calculate the mass of NaHCO_3

\text{ Mass of }NaHCO_3=\text{ Moles of }NaHCO_3\times \text{ Molar mass of }NaHCO_3

Molar mass of sodium bicarbonate = 84 g/mol

\text{ Mass of }NaHCO_3=(0.243moles)\times (84g/mole)=20.4g

Thus, the theoretical yield of sodium bicarbonate in grams is, 20.4 grams.

4 0
3 years ago
Write the ions present in a solution of na2co3. express your answers as chemical formulas separated by a comma. offset subscript
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Na₂CO₃ → 2Na⁺ + CO₃²⁻

CO₃²⁻ + H₂O ⇄ HCO₃⁻ + OH⁻

HCO₃⁻ + H₂O ⇄ CO₂·H₂O + OH⁻

Na⁺, CO₃²⁻, HCO₃⁻, OH⁻
4 0
3 years ago
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