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Inessa05 [86]
3 years ago
7

X + Y XY + heat What happens as the temperature is increased? [X] remains constant. [X] increases. [X] decreases.

Chemistry
2 answers:
TEA [102]3 years ago
6 0

The given reaction is exothermic,

X + Y ----> XY + Heat

Heat is a product. So, if the temperature is increased, the equilibrium is shifted towards the reactants. So, the <u>[X] increases</u>.

Vilka [71]3 years ago
4 0

Answer: [X] increases.

Explanation:  

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

For the given equation:

X+Y\rightarrow XY+heat

This is a type of Exothermic reaction because heat is released in the reaction.

If the temperature is increased, so according to the Le-Chatlier's principle , the equilibrium will shift in the direction where decrease in temperature occurs. As, this is an exothermic reaction, reverse reaction will decrease the temperature. Hence, the equilibrium will shift in the backward direction and thus [X] increases.

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A can of hairspray is crushed down to half its normal volume. What will
erik [133]

Answer:

pressure doubles

Explanation:

they are inversly preportional

6 0
3 years ago
How much heat is required to melt 20 g of gold at 1064.18 °C with a heat of fusion of 64 J/g *
andrew-mc [135]

Answer:

1280J are required.

Explanation:

Heat of fusion is defined as the amount of heat required to change its state from liquid to solid at its melting point at constant pressure.

As heat of fusion of gold is 64J/g, there are required 64J to melt 1g of gold at its melting point. The energy required to melt 20g is:

20g * (64J/g) =

1280J are required

6 0
3 years ago
Help me on this science question.
mel-nik [20]
The answer is Amarillo
6 0
3 years ago
In the coal-gasification process, carbon monoxide is converted to carbon dioxide via the following reaction: CO (g) + H2O (g) ⇌
Oksana_A [137]

Answer: Equilibrium constant is 0.70.

Explanation:

Initial moles of  CO = 0.35 mole

Volume of container = 1 L

Initial concentration of CO=\frac{moles}{volume}=\frac{0.35moles}{1L}=0.35M

Initial moles of  H_2O = 0.40 mole

Volume of container = 1 L

Initial concentration of H_2O=\frac{moles}{volume}=\frac{0.40moles}{1L}=0.40M

equilibrium concentration of CO=\frac{moles}{volume}=\frac{0.18moles}{1L}=0.18M [/tex]

The given balanced equilibrium reaction is,

                            CO(g)+H_2O(g)\rightleftharpoons CO_2(g)+H_2(g)

Initial conc.            0.35 M       0.40M       0     0

At eqm. conc.    (0.35-x) M   (0.40-x) M   (x) M    (x) M

The expression for equilibrium constant for this reaction will be,

K_c=\frac{[CO_2]\times [H_2O]}{[CO]\times [H_2O]}

K_c=\frac{x\times x}{(0.40-x)(0.35-x)}

we are given : (0.35-x)= 0.18

x = 0.17

Now put all the given values in this expression, we get :

K_c=\frac{0.17\times 0.17}{(0.40-0.17)(0.35-0.17)}

K_c=0.70

Thus the value of the equilibrium constant is 0.70.

5 0
3 years ago
The addition of NaOH to water would result in which of the following?
EleoNora [17]

Answer:

A decrease in [H3O+] and an increase in pH (option a)

Explanation:

Equilibrium of water is shown in this equation

2H₂O  ⇄  H₃O⁺  +  OH⁻

When you add NaOH, you are modifying [OH⁻]

NaOH  →   Na⁺  +  OH⁻

In equilibrium of water, the [OH⁻] increases

2H₂O   ⇄   ↓  H₃O⁺   +   OH⁻  ↑

As the [OH⁻] increases, by Le Chatellier, the equilibrium tends to decrease [H₃O⁺].

If the [OH⁻] is higher, pH  is also high so the solution of water and sodium hydroxide would be totally basic.

3 0
3 years ago
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