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<u>Answer:</u> The molar mass of unknown triprotic acid is 97.66 g/mol
<u>Explanation:</u>
To calculate the molarity of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of triprotic acid
are the n-factor, molarity and volume of base which is NaOH.
We are given:
Putting values in above equation, we get:
To calculate the molecular mass of solute, we use the equation used to calculate the molarity of solution:
We are given:
Molarity of solution = 0.0077 M
Given mass of triprotic acid = 0.188 g
Volume of solution = 250 mL
Putting values in above equation, we get:
Hence, the molar mass of unknown triprotic acid is 97.66 g/mol
24.25 moles of NO can be produced using 97 moles of HNO3.
<h3>What is balanced chemical equation?</h3>Equal numbers of atoms from various elements are present in both the reactants and the products in balanced chemical equations. Varied elements' atom counts in the reactants and products of unbalanced chemical equations are different.
3 Cu + 8HNO3 g → 3 Cu(NO3)2 + 2 NO + 4 H2O
The number of moles consumed can be calculated using comparing with coefficients in the balanced reaction .
So , from above eq we get that 8 moles of HNO3 are consumed to make 2 moles of NO.
⇒ 8 HNO3⇔2 NO
⇒ 1 HNO3⇔ 1/4 NO
This means that for each mole of HNO3 produces 1/4 moles of NO.
So , for 97 moles of HNO3 , moles of NO can be made,
So, total moles of NO made are 24.25 moles.
Lean more about balanced reactions here brainly.com/question/26694427
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