The grams of 22.9 % sugar solution that contain 68.5 g of sugar is 299.13 g of solution
<u><em>calculation</em></u>
22.9% means that there are 22.9 g of sugar in 100 g of solution.
what about 68.5 g of sugar
- <em>by cross multiplication</em>
=[(68.5 g sugar x 100 g solution) /22.9 g sugar] =299.13 g of solution
Nb; <em>g sugar cancel each other</em>
<span>What kind of geometry does the following molecule have? CF4 - </span>Tetrahedral
The description of an ideal gas is as follows:
- They have a small mass
- They have a small volume
- They have no intermolecular forces
<h3>WHAT IS AN IDEAL GAS?</h3>
An ideal gas is a theoretical gas composed of many randomly moving particles that do not engage in any inter-particle interactions.
An ideal gas obeys all the gas laws and possess the following characteristics:
- They have a small mass
- They have a small volume
- They have no intermolecular forces
Learn more about gas laws at: brainly.com/question/1437490
I would say the answer is C. Mutualism
The standard addition equation is as followsI_(S+X) (V/V_O )=I_X+I_X/[X]_i [S]_4 (V_S/V_0 ) Here, [X]_i is the initial concentration of analyte, [S]_i is the initial concentration of standard, I_X is signal for analyte, I_(S+X) is signal for standard and analyte, V_0 is the initial volume, V_S is the added standard volume, and V is the total volume.Added volume of standard V_S is-23.3 mL. Initial volume of the sample V_0 is 10.00 mL. Initial concentration of standard ([S]_i) is 0.156 ng/mL.[X]_i= -[S]_i (V_S/V_0 )〖[X]〗_(i )= -(0.156 ng/mL)((-23.3 mL)/(10.00 mL))=0.363 ng/mL
Concentration of U(III) in ground sample is 0.363 ng/mL
