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Zanzabum
3 years ago
13

This is algebra 1 math problem f (×)=2/5x+10

Mathematics
1 answer:
Alina [70]3 years ago
3 0
To find the inverse, interchange the variables and solve for y.

f^−1(x)=−25+5x/2
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The number of bacteria in a culture is increasing according to the law of exponential growth. After 3 hours, there are 200 bacte
VMariaS [17]

Answer:

Step-by-step explanation:

200(1+r)⁵⁻³ = 200(1+r)² = 800

(1+r)² = 4

1+r = 2

r = 100%

800(1+r)⁷⁻⁵ = 800·2² = 3200

7 0
3 years ago
Jessie has some nickels, dimes, and quarters in her bank. The number of coins is 30. The expression 0.05n + 0.10d + 0.25q repres
goldfiish [28.3K]

Answer:

n = 12 nickels

d = 11 dimes

q = 7 quarters

Step-by-step explanation:

.05n + .1d + .25q = 3.45

n + d + q = 30

n = q + 5

n = 12

d = 11

q = 7

8 0
3 years ago
How do i solve c =0.95,n=12
Elden [556K]

Answer:

  • c = \frac{19}{20}
  • n= 12

5 0
3 years ago
Factor: a^2 m + 5am – 30m
DIA [1.3K]
I am gonna go with C.
6 0
3 years ago
A 0. 0427 kg racquetball is moving 22. 3 m/s when it strikes a stationary box. The ball bounces back at 11. 5 m/s, while the box
andreyandreev [35.5K]

To solve the question we must know about the conservation of momentum.

<h2>Conservation of Momentum</h2>

According to the law of conservation of momentum, when two bodies collide with each other then their momentum is conserved if no external force acts on the system. therefore, the combined momentum of the two objects before collision will be equal to the combined momentum of the two objects after the collision.

the momentum of the two objects before the collision

                       = momentum of the two objects after the collision

The mass of the box is 0.30141 kg.

<h2>Explanation</h2>

Given to us

  • Mass of racquetball, m = 0.0427 kg,
  • Velocity of racquetball before Collision,  \bold{u_1} = 22.3 m/s,
  • Velocity of box before Collision,\bold{ u_2}  = 0 m/s,
  • Velocity of racquetball after Collision, \bold{v_1} = 11.5 m/s,
  • Velocity of box after Collision, \bold{v_2} = 1.53 m/s,

<h3>Assumption</h3>

Let the mass of the box be M.

<h3>Conservation Of Momentum</h3>

Momentum before collision = Momentum after collision

mu_1 + Mu_2 = mv_1 + Mv_2

given, the box was stationary before the collision,

mu_1 + Mu_2 = mv_1 + Mv_2\\\\&#10;mu_1 + 0 = mv_1 + Mv_2\\\\&#10;mu_1  - mv_1 = Mv_2\\\\&#10;M= \dfrac{mu_1  - mv_1}{v_2}

Substituting the values,

M= \dfrac{mu_1  - mv_1}{v_2}\\\\&#10;M = \dfrac{(0.0427 \times 22.3)  - (0.0427\times 11.5)}{1.53}\\\\&#10;M = 0.30141\ kg

Hence, the mass of the box is 0.30141 kg.

Learn more about Conservation of Momentum:

brainly.com/question/2141713

3 0
3 years ago
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