Answer:
107
Step-by-step explanation:
Answer:
Solve what
Step-by-step explanation:
That's about as much as you can simplify this problem.
I hope this helps! :)
Answer:
Venom C is 0.625 times as potent as venom A.
Step-by-step explanation:
We are given that venom A is four times as potent as venom B.
Venom C is 2.5 times as potent as Venom B.
We have to find that how many times as potent is venom C is compared to venom A.
Let Venom B =x
Then Venom A=
Venom C=
Hence, venom C is 0.625 times as potent as venom A.
Answer:
y = 4sin [(1/2)t - (4/3)π ] - 2
Step-by-step explanation:
For this question, do not be intimidated by the terminology, just realize the following:
for y = a sin [ (2π/T) t ]
a = amplitude = given as 4
T = period = given as 4π
phase shift is simply horizontal shift, positive values means the graph moves by that amount to left and negative values means the graph moves to the right.
vertical shift ... is well a shift vertically. positive values move the graph up vertically and negative values move the graph down vertically.
so... if we start with the basic formula:
y = a sin [ (2π/T) t ]
given a = 4 and T = 4π (substitute these values into the formula)
y = (4) sin [ (2π/4π) t ] = (4) sin [ (1/2) t ]
y = 4sin [(1/2)t ]
Now for the shifts:
given phase shift, aka horizontal shift is -(4/3)π, equation becomes
y = 4sin [(1/2)t - (4/3)π ]
given vertical shift is -2, the equation simply becomes
y = 4sin [(1/2)t - (4/3)π ] - 2
