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lidiya [134]
3 years ago
10

the diameter and hught of this cylinder are equal to the side length, S, of the cube in wich cylinder is inscribed. what is the

expression for the cylinder's volumes ?
Mathematics
1 answer:
Olenka [21]3 years ago
3 0

The fomula for the volume of a cylinder is

... V = πr²·h

You have r=s/2 and h=s, so this becomes

... V = π(s/2)²·s

... V = (π/4)s³

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F(x)=x^3+3
lawyer [7]

Answer:

  (a)   -3/4

  (b)  -0.75

  (c)  -0.75

Step-by-step explanation:

It's a bit hard to tell what constitutes an "iteration" when using the bisection method to approximate a polynomial root. For the purpose here, we'll say one iteration consists of ...

  • evaluating the function at the midpoint of the bracketing interval
  • choosing a smaller bracketing interval
  • identifying the x-value known to be closest to the solution

Thus, the result of the iteration consists of a bracketing interval and the choice of one of the interval's ends as the solution approximation.

__

(a) We observe that the graphs intersect in the interval (-1, 0). For the first iteration, we evaluate f(x)-g(x) at x=-1/2. This tells us the solution is in the interval (-1, -1/2). The x-value closest to the root is x=-1/2.

For the second iteration, we evaluate the function f(x)-g(x) at x=-3/4. This tells us the solution is in the interval (-1, -3/4). The x-value closest to the root is x=-3/4.

For the third iteration, we evaluate the function f(x)-g(x) at x=-7/8. This tells us the solution is in the interval (-7/8, -3/4). The x-value closest to the root is x=-3/4.

__

(b) The graph tells us the solution is approximately 0.7549. Rounded to 2 decimal places, the solution is approximately 0.75.

__

(c) The above solution found after 3 iterations rounded to 2 decimal places is exactly 0.75.

__

See the attached table for function values.

_____

<em>Comment on bisection iteration</em>

Since you cut the interval containing the root in half with each iteration, you gain approximately one decimal place for each 3 iterations. When the function value is very nearly zero at one of the interval endpoints, it can take many more iterations to achieve a better result.

Here, it takes 4 more iterations before an x-value becomes closer to the solution (x≈-97/128). And it takes one more iteration to move the end of the interval away from -3/4. After these 5 more iterations (8 total), the solution is known to lie in the interval (-97/128, -193/256). The corresponding solution approximation is -193/256. It is still only correct to 2 decimal places.

5 0
3 years ago
The radius of a circle is 13 in. Find its area in terms of pi​
grigory [225]

Answer:

A≈530.93in²

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Can someone Create a word scenario for 2x+0?
zimovet [89]
James runs 1 mile every 2 min. How many miles does he run every 3 mins?
8 0
3 years ago
Can somebody help me ? please .. if you answer you’ll get 20 points &amp; brainlyiest if correct! ( sorry i might have spelled b
valkas [14]

Answer: I think it should be a: 1/4 inch

Step-by-step explanation:

5 0
3 years ago
Martin says that f(x)=2(4)^x starts at 4 and has a constant ratio of 2. What error did Martin make? Explain.
grigory [225]

Answer:

A general exponential equation is written as:

f(x) = A*(r)^x

Where:

A is the initial value, this is the value that the function takes when x = 0.

r is the rate of growth

x is the variable.

In this case, the function is:

f(x) = 2*(4)^x

The initial value is:

f(0) = 2*(4)^0 = 2*1 = 2

The initial value is 2.

And the rate of growth is 4.

So Martin seems to mixed these two values (he said initial value = 4, and rate  = 2, which is the opposite of what we found)

8 0
2 years ago
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