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choli [55]
4 years ago
13

68 decreased by vanessa’s score is 16

Mathematics
2 answers:
madam [21]4 years ago
6 0

Answer:

Vanessa's score is 52

Step-by-step explanation:

You can solve this by subtracting the final number from the first number.

 68

<u>- 16</u>

52

snow_lady [41]4 years ago
3 0

Answer:

84

Step-by-step explanation:

just add the numbers together

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Alivia is writing the program for a video game. For one part of the game she uses the rule (x,y)➡️(x-3,y+4) to move points on th
Alika [10]
A) the output would be -9,4 because using the rule Alivia created (x,y)➡(x-3,y+4) -6 (which is the x value) subtract 3 equals -9. 0, which is the y value plus 4 equals four.

b) The output would be 0,0 because using the same rule 3 subtract 3 is 0 and -4 plus 4 is 0.

c) Honestly I tried to determine whether the rule was a function and I am having a hard time determining. But I can tell you that x values cannot have more than one y value while y can have more than on x value.

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3 years ago
Rqw-xeix-ogw<br>Girls come on ​
Olegator [25]

Answer:

no bro

Step-by-step explanation:

6 0
3 years ago
Can anyone help me identify the center &amp; radius pls
Vlad1618 [11]

Answer:

see explanation

Step-by-step explanation:

the equation of a circle centred at the origin is

x² + y² = r² ( r is the radius )

(11)

- 81 + x² = - y² ( add y² to both sides )

- 81 + x² + y² = 0 ( add 81 to both sides )

x² + y² = 81 ← in standard form

with centre = (0, 0 ) and r = \sqrt{81} = 9

(12)

y² + x² - 196 = 0 ( add 196 to both sides )

x² + y² = 196 ← in standard form

with centre = (0, 0 ) and r = \sqrt{196} = 14

7 0
2 years ago
If someone could help u would be amazing!!!!!
GaryK [48]
Tasha's mistake is in Step 4
she has a negative sign in front of the fraction and she has a negative exponent on the 4 in the denominator
3 0
3 years ago
Given the conditional statement ~p -&gt; q which statement is logically equivalent?​
icang [17]

Any implication is logically equivalent to its contrapositive. In other words,

¬<em>p</em> ⇒ <em>q</em>   ⇔   ¬<em>q</em> ⇒ <em>p</em>

(¬ means the same thing as ~, "not")

To prove this: recall that

<em>p</em> ⇒ <em>q</em>   ⇔   ¬<em>p</em> ∨ <em>q</em>

This is because <em>p</em> ⇒ <em>q</em> is true if <em>p</em> is false, or both <em>p</em> and <em>q</em> are true, i.e.

<em>p</em> ⇒ <em>q</em>   ⇔   ¬<em>p</em> ∨ (<em>p</em> ∧ <em>q</em>)

Disjunction (∨ or "or") distributes over conjunction (∧ or "and"), so that

<em>p</em> ⇒ <em>q</em>   ⇔   (¬<em>p</em> ∨ <em>p</em>) ∧ (¬<em>p</em> ∨ <em>q</em>)

but ¬<em>p</em> ∨ <em>p</em> is always true, or a tautology, so we're just left with ¬<em>p</em> ∨ <em>q</em>.

Then

¬<em>p</em> ⇒ <em>q</em>   ⇔   <em>p</em> ∨ <em>q</em>

…   ⇔   <em>q</em> ∨ <em>p</em>

…   ⇔   ¬(¬<em>q</em>) ∨ <em>p</em>

…   ⇔   ¬<em>q</em> ⇒ <em>p</em>

4 0
3 years ago
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