3 years ago

Answer question from picture.

1 answer:

4 0

The limit (as 'x' approaches zero) of x²/(2x+1) is

0 / (0+1) = 0 .

You get this by substituting the limit in place of 'x'.

Sometimes that doesn't work. Sometimes it gives you
monstrosities like 0/0, or 1/0, or ∞/∞ .

But it works for this one. There's nothing wrong with 0/1 = zero .

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Determine whether the function has a maximum or minimum value. <br> f(×)= x^2+9

PtichkaEL [24]

$f(x)= x^2+9\\\\for\ each\ x\in R\\\\x^2 \geq 0\ \ \ \Rightarrow\ \ \ x^2+9 \geq 9\ \ \ \Rightarrow\ \ \ f(x) \geq 9\\\\y_{min}=9\\ y_{max}\ \ \ \rightarrow\ \ \ not\ exist$