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2 years ago

I’m so confused, I will try to mark brainliest, sorry if I can’t figure it out.

Mathematics

2 answers:

jonny [76]2 years ago

7 0

Answer and Step-by-step explanation:

The answers are:

x + 105 = 180 (Supplementary angles = 180 degrees)

x = z (Vertical angles are congruent)

180 - z = y (Supplementary angles = 180 degrees)

#teamtrees #PAW (Plant And Water)

Genrish500 [490]2 years ago

5 0

Answer:

$x^{\circ}+105^{\circ}=180^{\circ},\\x^{\circ}=z^{\circ},\\180^{\circ}-z^{\circ}=y^{\circ}$

Step-by-step explanation:

Statement 1:

True - These two angles are supplementary (add up to 180 degrees) because they form one side of a line.

Statement 2:

True - These two angles are vertical angles (opposite to each other at intersection of two lines). All vertical angles are equal.

Statement 3:

False - These two angles are vertical and therefore are equal. Thus, they cannot have a difference of 105.

Statement 4:

False - Two of these angles form one side of a line which is equal to 180 degrees. Since the third angle is greater than zero, they cannot all add up to 180 degrees.

Statement 5:

True - These two angles are supplementary (add up to 180 degrees) because they form one side of a line.

Statement 6:

False - These two angles are supplementary (add up to 180 degrees) because they form one side of a line and therefore cannot be equal to 105.

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2 years ago

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2 years ago

The radius of a spherical balloon is measured as 20 inches, with a possible error of 0.03 inch. Use differentials to approximate

soldi70 [24.7K]

Answer:

a) $V = 33510.322\,in^{3}$ , b) $A_{s} = 5026.548\,in^{2}$ , c) $\% V = 0.450\,\%$ , $\%A_{s} = 0.300\,\%$ .

Step-by-step explanation:

The volume and the surface area of the sphere are, respectively:

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$A_{s} = 4\pi \cdot r^{2}$

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$V = \frac{4}{3}\pi \cdot (20\,in)^{3}$

$V = 33510.322\,in^{3}$

b) The surface area of the sphere is:

$A_{s} = 4\pi \cdot (20\,in)^{2}$

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c) The total differentials for volume and surface area of the sphere are, respectively:

$\Delta V = 4\pi\cdot r^{2}\,\Delta r$

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$\Delta A_{s} = 15.080\,in^{2}$

Relative errors are presented hereafter:

$\%V = \frac{\Delta V}{V}\times 100\%$

$\%V = \frac{150.796 \,in^{3}}{33510.322\,in^{3}}\times 100\,\%$

$\% V = 0.450\,\%$

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$\% A_{s} = \frac{15.080\,in^{2}}{5026.548\,in^{2}}\times 100\,\%$

$\%A_{s} = 0.300\,\%$

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