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3 years ago

Which shows the formula for an Organic acid

1 answer:

3 0

Answer:
The formula of Organic acid is as follow,

R-COOH

Explanation:
The class of organic acids is called Carboxylic Acids. In above general structure, R is alkyl group and can vary. While -COOH is the functional group.
Carboxylic Acids has the tendency to loose protons and their pKa value depends upon the alkyl group. For example the pKa value of Acetic acid (R = -CH₃) is 4.7. The driving force for this acidity is the stability of carboxylate (conjugate base) due resonance. i.e

RCOOH ⇄ RCOO⁻ + H⁺
Where;
RCOO⁻ = Carboxylate Ion (Conjugate base)

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If a black ball is denser than a white ball of the same size, what does the black ball have??

yKpoI14uk [10]

Answer: The black ball will have more mass than the white ball.

Explanation: Density of a substance is defined as the ratio of mass and volume occupied by the substance.

Mathematically,

$Density=\frac{Mass}{Volume}$

We are given that the two balls are of same size, which means that the volume of both the balls are same. We are also given that the black ball is more dense than the white ball, which means that the black ball will have more mass.

As, $Density\propto Mass$

7 0

3 years ago

Fill in the coefficients that will balance the following reaction:

vfiekz [6]

6NaC₂H₃O₂ + Fe₂O₃ → 2Fe(C₂H₃O₂)₃ + 3Na₂O

Explanation:

Given equation;

NaC₂H₃O₂ + Fe₂O₃ → Fe(C₂H₃O₂)₃ + Na₂O

To find the coefficient that will balance this we equation, let us set up simple mathematical algebraic expressions that we can readily solve.

Let us have at the back of our mind that, in every chemical reaction, the number of atom is usually conserved.

aNaC₂H₃O₂ + bFe₂O₃ → cFe(C₂H₃O₂)₃ + dNa₂O

a, b, c and d are the coefficients that will balance the equation.

conserving Na; a = 2d

C: 2a = 6c

H: 3a = 9c

O; 2a + 3b = 6c + d

Fe: 2b = c

let a = 1

solving:

2a = 6c

2(1) = 6c

c = $\frac{2}{6} = \frac{1}{3}$

2b = c

b = $\frac{1}{2} x \frac{1}{3}$ = $\frac{1}{6}$

d = 2a + 3b - 6c = 2(1 ) + (3 x $\frac{1}{6}$ ) - (6 x $\frac{1}{3}$ ) = $\frac{1}{2}$

Now multiply through by 6

a = 6, b = 1, c = 2 and d = 3

6NaC₂H₃O₂ + Fe₂O₃ → 2Fe(C₂H₃O₂)₃ + 3Na₂O

learn more:

Balanced equation brainly.com/question/9325293

#learnwithBrainly

6 0

3 years ago

Assume that all of this fossil fuel is in the form of octane (C8H18) and calculate how much CO2 in kilograms is produced by worl

AnnZ [28]

The given question is incomplete. the complete question is:

The world burns the fossil fuel equivalent of approximately $9.50\times 10^{12}$ kg of petroleum per year. Assume that all of this petroleum is in the form of octane. Calculate how much CO2 in kilograms is produced by world fossil fuel combustion per year.( Hint: Begin by writing a balanced equation for the combustion of octane.)

Answer: $29\times 10^{12}kg$

Explanation:

Combustion is a chemical reaction in which hydrocarbons are burnt in the presence of oxygen to give carbon dioxide and water.

According to the law of conservation of mass, mass can neither be created nor be destroyed. Thus the mass of products has to be equal to the mass of reactants. The number of atoms of each element has to be same on reactant and product side. Thus chemical equations are balanced.

$2_C8H_{18}+17O_2\rightarrow 16CO_2+18H_2O$

To calculate the moles :

$\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}$

$\text{Moles of octane}=\frac{9.50\times 10^{12}\times 10^3g}{114g/mol}=0.083\times 10^{15}moles$

According to stoichiometry :

As 2 moles of octane give = 16 moles of $CO_2$

Thus $0.083\times 10^{15}moles$ of octane give = $\frac{16}{2}\times 0.083\times 10^{15}=0.664\times 10^{15}moles$ of $CO_2$

Mass of $CO_2=moles\times {\text {Molar mass}}=0.664\times 10^{15}moles\times 44g/mol=29.2\times 10^{15}g=29.2\times 10^{12}kg$

Thus $29\times 10^{12}kg$ of $CO_2$ is produced by world fossil fuel combustion per year.

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3 years ago

Will a cold snowball give off cold air?

rewona [7]

No, Heat moves from concentrations of high to low.

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3 years ago

Read the following chemical equations.

lora16 [44]

This problem is providing two reduction-oxidation (redox) reactions in which the oxidized and reduced species can be identified by firstly setting the oxidation number of each element:

Reaction 1: 2K⁺I⁻ + H₂⁺O₂⁻ ⇒2K⁺O⁻²H⁺ + I₂⁰

Reaction 2: Cl₂⁰ + H₂⁰ ⇒ 2H⁺CI⁻

Next, we can see that iodine is being oxidized and oxygen reduced in reaction #1 and chlorine is being reduced and hydrogen oxidized in reaction #2 because the oxidized species increase the oxidation number whereas the reduced ones decrease it.

In such a way, the correct choice is C.

Learn more:

(Redox reactions) brainly.com/question/13978139

8 0

2 years ago