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Maslowich
3 years ago
12

What to the third power is equal to 729

Mathematics
2 answers:
atroni [7]3 years ago
5 0

If you had absolutely no idea, then you'd have roughly two choices
of how to find it:

#1).  Try numbers until you find the right one.

        Pick a number.
        Cube it.
        If you get less than 729, go back and try a bigger number.
        If you get more than 729, go back and try a smaller number.
        Eventually you find the right one.  

Try 1.        1³ = 1 .            Too small.
Try 2.        2³ = 8 .            Still too small.
Try 5.        5³ = 125 .        Still too small.
Try 20.     20³ = 8,000.      Ooops.  Too big.
Try 10.     10³ = 1,000       Too big.
Try 8.         8³ = 512.         Oooo.  Too small, but maybe getting close.
Try 8.5.    8.5³ = 614.125   Still too small, but very close.
Try 9.         9³ = 729 .       That's it !            yay !


#2).  x³ = 729

Take the log of each side:      log(x³) = log(729)

                                         3 log(x)  =  log(729)

Divide each side by  3 :         log (x)  =  (1/3) log(729)

Look up log(729) :                 log(x)  =  (1/3) (2.86272...)

                                                      =    0.95424...
Raise 10 to the power
of each side:                      10^log(x)  =  10⁰·⁹⁵⁴²⁴···  

                                               x        =  8.99994...

                                         (That's the way it is with logs.
                                          They never come out even.)
faust18 [17]3 years ago
3 0
9 to the third power is equal to 729. 9x9x9 = 729.
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kakasveta [241]

<u>Solution-</u>

From the figure,

AE = 2.4

EB = 2.8

BC = 11.7


Area of rectangle 1 = 8.68 sq.in

\Rightarrow FH \times HI=8.68

\Rightarrow EB \times HI=8.68  (∵ sides of the rectangle 2)

\Rightarrow 2.8 \times HI=8.68

\Rightarrow HI=3.1


Area of Triangle 1 = 6.48 sq.in

\Rightarrow \frac{1}{2}\times AE \times EG= 6.48

\Rightarrow \frac{1}{2}\times AE \times (EF+FG)= 6.48

\Rightarrow \frac{1}{2}\times AE \times (EF+HI)= 6.48  (∵ sides of the rectangle 1)

\Rightarrow EF+3.1= 5.4

\Rightarrow EF=2.3

\Rightarrow BH=2.3  (∵ sides of the rectangle 2)


BC = BH+HI+IC

\Rightarrow 11.7= 2.3+3.1+IC

\Rightarrow IC=6.3


The area of Rectangle 2,

=EB\times BH =2.8\times 2.3=6.44\ sq.in


The area of Triangle 2,

\frac{1}{2}\times GI \times IC=\frac{1}{2}\times EB \times IC=\frac{1}{2}\times 2.8 \times 6.3=8.82\ sq.in


The area of the whole figure = Area of Triangle 1 + Area of rectangle 1 + Area of Triangle 2 + Area of rectangle 2

= 6.48+8.68+8.82+6.44=30.42 sq.in


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Step-by-step explanation:

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now we figure out how to make these numbers into our terms of this sequence

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2 years ago
dave and his sister picked out two pumpkins at the pumpkin patch. the pumpkins cost $0.47 per pound. davids pumpkin weighed 13.2
Andrei [34K]
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3 0
4 years ago
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nadezda [96]

Answer:

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Rounding to the nearest whole number

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5 0
4 years ago
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