Answer:
393.1 KPa
Explanation:
Now we have to use the general gas equation;
P1V1/T1 = P2V2/T2
P1= initial pressure of the gas= 1.00atm
V1 = initial volume= 700.0 ml
T1= initial temperature= 0.0°C +273= 273K
V2= final volume= 200.0 ml
T2= final temperature =30.0°C +273= 303 K
P2= final pressure =????
Therefore;
P2= P1V1T2/ V2T1
P2= 1.00 × 700.0 × 303/ 200.0 × 273
P2= 3.88 atm
But
1 atm = 101.325 kilopascals
Therefore 3.88 atm = 3.88 × 101.325 kilopascals = 393.1 KPa
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