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Maksim231197 [3]
3 years ago
9

In general, weathering tends to occur more rapidly in warm climates than in cool climates. How does this trend explain the effec

t of temperature on erosion rates?
Chemistry
1 answer:
lidiya [134]3 years ago
5 0

Answer:

See explanation

Explanation:

Weathering refers to the breakdown of rocks to form soil. There are several agents of weathering.

In warmer regions, there are more vegetation and microorganisms and they increase the rate of biological weathering.

Since weathering leads to the formation of soil and the rate of weathering is greater in warmer climates, it also follows that as temperature increases and more soil is formed, erosion will happen faster at this higher temperature owing to the presence of more soil compared to colder climates.

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What is the mass in grams of 0.250 mol CH2Cl2?
Orlov [11]

Answer:

21.2 grams CH2Cl2

Explanation:

Number of moles: .25

Molar mass of CH2Cl2: 84.93 g/mol

Mass in grams: 84.93(0.250) = 21.2325

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A chemical property of soda ash is that it is an alkaline compound , of pH 11.6 in aqueous solution. The chemical name of soda ash is sodium carbonate. It is a sodium salt of carbonic acid and occurs as a white crystalline compound. It has a cooling alkaline taste. It can be found in the ashes of many plants. It is produced in large quantities from sodium chloride (common salt). It can be found as a mineral in mineral deposits of natron usually in seasonal lakes when the lakes dry up.
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The two isotopes of chlorine are LaTeX: \begin{matrix}35\\17\end{matrix}Cl35 17 C l and LaTeX: \begin{matrix}37\\17\end{matrix}C
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<u>Answer:</u> The percentage abundance of _{17}^{35}\textrm{Cl} and _{17}^{37}\textrm{Cl} isotopes are 77.5% and 22.5% respectively.

<u>Explanation:</u>

Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.

Formula used to calculate average atomic mass follows:

\text{Average atomic mass }=\sum_{i=1}^n\text{(Atomic mass of an isotopes)}_i\times \text{(Fractional abundance})_i   .....(1)

Let the fractional abundance of _{17}^{35}\textrm{Cl} isotope be 'x'. So, fractional abundance of _{17}^{37}\textrm{Cl} isotope will be '1 - x'

  • <u>For _{17}^{35}\textrm{Cl} isotope:</u>

Mass of _{17}^{35}\textrm{Cl} isotope = 35 amu

Fractional abundance of _{17}^{35}\textrm{Cl} isotope = x

  • <u>For _{17}^{37}\textrm{Cl} isotope:</u>

Mass of _{17}^{37}\textrm{Cl} isotope = 37 amu

Fractional abundance of _{17}^{37}\textrm{Cl} isotope = 1 - x

Average atomic mass of chlorine = 35.45 amu

Putting values in equation 1, we get:

35.45=[(35\times x)+(37\times (1-x))]\\\\x=0.775

Percentage abundance of _{17}^{35}\textrm{Cl} isotope = 0.775\times 100=77.5\%

Percentage abundance of _{17}^{37}\textrm{Cl} isotope = (1-0.775)=0.225\times 100=22.5\%

Hence, the percentage abundance of _{17}^{35}\textrm{Cl} and _{17}^{37}\textrm{Cl} isotopes are 77.5% and 22.5% respectively.

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