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3 years ago

Which of he following is a secondary alkanol?

Chemistry

1 answer:

hodyreva [135]3 years ago

5 0

Answer: Thus $CH_3CH(OH)CH_3$ is a secondary alkanol.

Explanation:

Alkanol are compounds which contains carbons bonded by single bonds and contains hydroxy (-OH) as functional group.

Primary alkanol are those compounds which contain hydroxyl group attached a carbon which is further attached to a single carbon atom. Example: $CH_3CH_2CH_2OH$ and $CH_3CH_2CH_2CH_2OH$

Secondary alkanol are those compounds which contain hydroxyl group attached to a carbon which is further attached to two more carbon atoms.Example: $CH_3CH(OH)CH_3$

Tertiary alkanol are those compounds which contain hydroxyl group attached to a carbon which is further attached to three more carbon atoms. Example: $C(CH_3)_3OH$

Thus $CH_3CH(OH)CH_3$ is a secondary alkanol.

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How do water molecules in the solid phase compare with water molecules in the gaseous phase?

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Salty is solid molecular in water

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3 years ago

Complete combustion of a compound containing hydrogen and carbon produced 2.641 g of carbon dioxide and 1.442 grams of water as

klio [65]

The empirical formula of hydrocarbon is C₃H₈

The molecular formula of hydrocarbon is C₆H₁₆

Empirical formula calculation

Hydrocarbon contain carbon and hydrogen

Step 1: find the mass carbon (C) in carbon dioxide (CO₂) and hydrogen (H ) in water

mass of of element = molar mass of element/ molar mass molecule x total mass of molecule

From periodic table the molar mass of C =12, for CO₂ = 12+( 16 x2) =44 g/mol, for H = 1.00 g/mol, for H₂O = (2 x1)+16 = 18 g/mol

mass of C = 12/44 x 2.641 =0.7203 g

since there are 2 atom of H in H₂O the molar mass of H = 1 x2 = 2 g/mol

mass of H is therefore = 2/18 x 1.442 =0.1602 g

Step 2: find the moles of C and H

moles = mass÷ molar mass

moles of C = 0.7203 g÷ 12 g/mol = 0.060 moles

moles of H = 0.1602÷ 1 g/mol = 0.1602 moles

Step 3: find the mole ratio of C and H by dividing each mole by smallest mole ( 0.06)

for C = 0.06/0.06 =1

For H = 0.1602/0.06 =2.67

multiply by 3 to remove the decimal

For C = 1 x3 =3

For H = 2.67 x3 =8

therefore the empirical formula = C₃H₈

The molecular formula calculation

[C₃H₈]n = 88.1 g/mol

[12 x 3)+( 1 x8)]n =88.1 g/mol

44 n = 88.1

divide both side by 44

n=2

therefore [C₃H₈]₂ = C₆H₁₆

7 0

3 years ago

Read 2 more answers

Choose the products that complete the reaction NaHCO3+HC2H3O2

Novosadov [1.4K]

Answer:

The products will be;

CO₂ + H₂O + NaC₂H₃O₂

Explanation:

We are given;

Two reactants NaHCO₃ and HC₂H₃O₂

We are supposed to determine the products;

We need to know that hydrogen carbonates reacts with acids to give water, carbon dioxide and a salt as the products.

Therefore;

In this case, sodium hydrogen carbonates (baking soda) reacts with acetic acid to form water, carbon dioxide and sodium acetate.
The equation for the reaction is;

NaHCO₃ + HC₂H₃O₂ → CO₂ + H₂O + NaC₂H₃O₂

Therefore, the products of the complete reaction between sodium hydrogen carbonate and acetic acid are CO₂ + H₂O + NaC₂H₃O₂

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3 years ago

NEED HELP FAST!20 pts for an easy worksheet

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On the bottom
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4 years ago

A sample of gas has a volume of 75.0 mL at 30.0 psi. Determine the pressure of the gas if its volume is changed to 15 mL and its

Assoli18 [71]

Answer:

5.995 psi

Explanation:

30 psi = 2.04 atm

75 mL = 0.075 L

15 mL = 0.015 L

0.075 L/ 2.04 atm = 0.015 L/x

0.075x = 0.0306

x = 0.408

0.408 atm = 5.995 psi

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3 years ago