According to (P)arenthesis (E)xponets (M)ultiply (D)ivide (A)dd (S)ubtract, it would be (1 / 7).
Since a calculator is involved in finding the answer, it makes sense to me to use a calculator capable of adding vectors.
The airplane's ground speed is 158 mph, and its heading is 205.3°.
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A diagram can be helpful. You have enough information to determine two sides of a triangle and the angle between them. This makes using the Law of Cosines feasible for determining the resultant (r) of adding the two vectors.
.. r^2 = 165^2 +15^2 -2*165*15*cos(60°) = 24975
.. r = √24975 ≈ 158.03
Then the angle β between the plane's heading and its actual direction can be found from the Law of Sines
.. β = arcsin(15/158.03*sin(60°)) = 4.7°
Thus the actual direction of the airplane is 210° -4.7° = 205.3°.
The ground speed and course of the plane are 158 mph @ 205.3°.
The matrices are
S =(4 11 T= ( -8 11
-3 -8) 3 4 )
Inverse of a matrix is a matrix derived from another matrix such that if you pre- multiply it with the original matrix you get a unit matrix.
if we multiply S and T
ST will be
( 4 11 × (-8 11 = ( 1 0
-3 -8) -3 -4) 0 1)
and also TS
( -8 11 × (4 11 = ( 1 0
-3 -4) -3 -8) 0 1)
therefore, matrices S and T are inverses of each other because ST = TS= I
.
<u>Answer</u>
y⁻¹ = ∛(4x+8)
<u>Explanation</u>
y=(1/4)x³ - 2.
To find the inverse of this equation, you first make x the subject of the formular.
y=(1/4)x³ - 2
Multiply both sides by 4;
4y = x³ - 8
Add 8 on both sides of the equation;
4y + 8 = x³
x³ = 4y + 8
Apply the cube root on both sides to get the value of x;
x = ∛(4y+8)
The inverse of y=(1/4)x³ - 2 is;
y⁻¹ = ∛(4x+8)
Differentiating an integral removes the integral.
f(x) = integral of dt/sqrt(t^3 + 2)
f'(x) = 1/sqrt(x^3 + 2)
f'(1) = 1/sqrt(1^3 + 2)
f'(1) = 1/sqrt(3) = sqrt(3)/3.
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