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love history [14]
3 years ago
5

A racecar is traveling at a constant speed of 120 miles per hour. How many feet does it travel in 6 seconds? Remember that 1 mil

e is 5280 feet.
Mathematics
1 answer:
snow_tiger [21]3 years ago
5 0

Answer:

1056 ft

Step-by-step explanation:

We need to convert the units from miles per hour to feet per second:

recall that i mile = 5280 ft, and one hour is 3600 seconds, so we do the conversion of the 120 miles per hour speed as follows:

120 \,\frac{mi}{h} = 120\,\frac{5280\,\,ft}{3600\,\,s} = \,176\,\,\frac{ft}{s}

which means that the car cover 176 ft in one second. Therefore, in 6 seconds it will cover 6 times this:

distance = 176 * 6 = 1056 ft

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tankabanditka [31]

Answer:

30.96 m^2

Step-by-step explanation:

Side length of the square is also the diameter of the semicircle so:

r = 0.5 * 12 m = 6 m

Since you want the area of the shaded area, you have to subtract the area of both semi circles from the area of the square:

Square Area - Semi Circle Area - Semi Circle Area = Shaded Region Area

(12 m * 12 m) - (0.5 * 3.14 * 6^2 m) - (0.5 * 3.14 * 6^2 m)

= 144 - 56.52 - 56.52

= 30.96 m^2

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3 years ago
What is the nearest value of d to the nearest hundredth
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The Answer to question is 2.05
6 0
3 years ago
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Martin is seating people in the cars of a roller coaster. Each car can seat 8 people. Six of the roller coaster cars are yellow
Mamont248 [21]

Answer:

The probability is 2/5

Step-by-step explanation:

Here, we want to calculate the probability that the first person will sit in a yellow roller coaster car

The number of cars to select from is 6 + 9 = 15 cars

The number of yellow cars is 6

So the probability that the first person selects a yellow roller coaster car to seat is 6/15 = 2/5

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2 years ago
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Step-by-step explanation:

6 0
3 years ago
Las edades de dos hermanos tienen una razón de 2 a 1. Cuando transcurran 4 años, la razón entre sus edades será de 8 a 6. ¿Cuánt
Nataly [62]

Answer:

The age of brothers are 4 years and 2 years respectively.

Step-by-step explanation:

We are given that the ages of two brothers have a ratio of 2 to 1. When 4 years have passed, the ratio of their ages will be 8 to 6.

Let the age of the first brother be 'x years' and the age of the second brother be 'y years'.

So, according to the question;

  • The first condition states that the ages of two brothers have a ratio of 2 to 1, that means;

                                      \frac{x}{y} =\frac{2}{1}  

                                      x=2y  -------------- [equation 1]

  • The second condition states that when 4 years have passed, the ratio of their ages will be 8 to 6, that means;

                                       \frac{x+4}{y+4}=\frac{8}{6}

                               6({x+4})=8}(y+4)

                               6x+24=8y+32

                               6(2y)+24=8y+32

                               12y-8y=32-24

                                    4y=8

                                     y=\frac{8}{4} = 2 years

Putting the value of y in equation 1 we get;

                                     x = 2y

                                      x = 2 \times 2 = 4 years

Hence, the age of brothers are 4 years and 2 years respectively.

3 0
3 years ago
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