Answer:


Step-by-step explanation:
Calculate the value of trigonometry function.
and 
Split the angle between 0 to 90° using trigonometry formula.



Therefore, cos(480°) = -0.5



Therefore, sin(480°) = 0.866
Answer:
The following list is in order from smallest to largest is 
Step-by-step explanation:
Let the numbers be 
To find the list in order from smallest to largest:

Rewritting the above numbers as below


Now arranging the numbers in order from smallest to largest


The arranged numbers can be written as

The following list is the order from smallest to largest is 
Answer:
Acellus, Eh? Answer Is Simple. 69%
Its 69 Because Thats the best number, and 69 is always the answer
In linear change, the two variables keep increasing or decreasing at the same speed.
the answer is 13/7 and here is the correct question
the answer is 13/7 and here is the correct questionwhen a customer wants pie for dessert you cut a whole pies into 7 equal slices...at the end of your shift 3/7 of. a cherry pie.2/7. of an apple pie.3/7 of a peach pie.and 5/7 of a blueberry pie remain...How much pie remains as a fraction of. a whole pie...
Answer:
13/7
Step-by-step explanation:
From the question, we have
3/7 of cherry pie
2/7 of apple pie
3/7 of peach pie
5/7 of blueberry pie
Now we have to add up all of these in order to get the total amount of pie
3/7 + 2/7 +3/7 +5/7
= (3+2+3+5)/7
=13/7
If expressed as a mixed fraction
= 1 6/7
In conclusion, 13/7 pie remains as a fraction of a whole.