In the figure below, what are k and m

There are 90 girls and 60 boys in the sixth grade at a middle school. Of these students, 7 girls and 2 boys write left-handed. W

Radda [10]

Answer:

6%

Step-by-step explanation:

90 + 60 = 150
7 + 2 = 9
Set up a proportion: $\frac{9}{150} = \frac{x}{100}$
Cross multiply, then divide: 9 × 100 = 900, 900 ÷ 150 = 6
So, 6% of students in 6th grade were left-handed

I hope this helps!

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3 years ago

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Past experience has indicated that the breaking strength of yarn used in manufacturing drapery material is normally distributed

vlabodo [156]

Answer:

95% two-sided confidence interval on the true mean breaking strength is (94.8cm, 99.2cm)

Step-by-step explanation:

Our sample size is 11.

The first step to solve this problem is finding our degrees of freedom, that is, the sample size subtracted by 1. So

$df = 11-1 = 10$ .

Then, we need to subtract one by the confidence level $\alpha$ and divide by 2. So:

$\frac{1-0.95}{2} = \frac{0.05}{2} = 0.025$

Now, we need our answers from both steps above to find a value T in the t-distribution table. So, with 10 and 0.025 in the two-sided t-distribution table, we have $T = 1.812$

Now, we find the standard deviation of the sample. This is the division of the standard deviation by the square root of the sample size. So

$s = \frac{4}{\sqrt{11}} = 1.2060$

Now, we multiply T and s

$M = Ts = 1.812*1.2060 = 2.19/tex]For the lower end of the interval, we subtract the sample mean by M. So the lower end of the interval here is[tex]L = 97 - 2.19 = 94.81 = 94.8$ cm