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3 years ago

What is 0.64 as a fraction in lowest terms

2 answers:

6 0

Write the decimal number as a fraction
(over 1)
0.64 = 0.64 / 1

Multiplying by 1 to eliminate 2 decimal places
we multiply top and bottom by 2 10's

Numerator = 0.64 × 10 × 10 = 64

Denominator = 1 × 10 × 10 = 100

Numerator/denominator = 64 / 100

Simplifying our fraction

= 64/100

= 16/25

crimeas [40]3 years ago

5 0

$0.64\to two\ digits\ after\ the\ decimal\ point\ therefore\ are\ hundredths\\\\0.64=\frac{64}{100}=\frac{64:4}{100:4}=\boxed{\frac{16}{25}}$

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I need help omg thanks !

coldgirl [10]

Answer:

<em>Option C.</em>

Step-by-step explanation:

If you subtract each value from the next one, you see the differences are different. Therefore, it is not linear. Now divide each value by the previous value. You get 1.7 each time.

Answer: Option C.

6 0

3 years ago

How many subsets of the set $\{1,2,3,4, 5, 6, 7, 8, 9, 10\}$ contain the number 5?

lianna [129]

For the given set of numbers:
<span>{1,2,3,4, 5, 6, 7, 8, 9, 10}
the number of elements
n=10
the total number of subsets is given by:
2^10=1024

</span>

6 0

3 years ago

Please help me with this.

OLga [1]

Swapping rows alters the sign of the determinant:

$\begin{vmatrix} x & y & z \\ -8 & 2 & -12 \\ u & v & w \end{vmatrix} = - \begin{vmatrix} x & y & z \\ u & v & w \\ -8 & 2 & -12 \end{vmatrix}$

Multiplying a single row by a scalar scales the determinant by the same amount:

$\begin{vmatrix} x & y & z \\ u & v & w \\ -8 & 2 & -12 \end{vmatrix} = -2 \begin{vmatrix} x & y & z \\ u & v & w \\ 4 & -1 & 6 \end{vmatrix}$

Then

$\begin{vmatrix} x & y & z \\ -8 & 2 & -12 \\ u & v & w \end{vmatrix} = -(-2) \begin{vmatrix} x & y & z \\ u & v & w \\ 4 & -1 & 6 \end{vmatrix} = 2\times(-6) = \boxed{-12}$

8 0

2 years ago

The first four terms of a sequence are shown below:

Marta_Voda [28]

Answer:

Step-by-step explanation:

Since each term is decreased by three $f(n+1)=f(n)-3$

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2 years ago

a fair coin is flipped 10 times. what is the probability of getting the same number of heads and tails

Dafna11 [192]

If you flip a coin one time, the probability to get a Head is

p = 1/2

The probability of not getting a head in a single toss is :

q = 1 - 1/2 = 1/2

Thus there is only one unique situation to get the same number of heads and tails : in 10 toss you need to get exactly five heads, it will means that the rest is the tails.

Now using Binomial theorem of probability, the probability of getting exactly x = 5 heads in a total of n = 10 tosses is :

P(X = 5) = $\frac{10!}{5!*5!} *(\frac{1}{2})^{5} *(\frac{1}{2})^{5}$ ≈ 0.246

So the probability of that is 24,6 %

Good Luck

3 0

2 years ago