The second one from the top shows a dilatation.
It increased by 3000$ for every 200,000$ increased in appraised value. Hope this helps❤️please rate
Answer:
Step-by-step explanation:
Suppose the dimensions of the playground are x and y.
The total amount of the fence used is given and it is 780 ft. In terms of x and y this would be 3x+2y=780 (we add 3x because we want it to be cut in the middle). Therefore, y= 780/2-3/2x. Now, the total area (A )to be fenced is
A=x*y= x*(390-3/2x)=-3/2 x^2+390x
Calculating the derivative of A and setting it equals to 0 to find the maximum
A'= -3x+390=0
This yields x=130.
Therefore y=780/2-3/2*130=195
Thus, the maximum area is 130*195=25,350ft^2
<h3>Answer: 32 degrees</h3>
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Work Shown:
Inscribed angle theorem
arc measure = 2*(inscribed angle)
arc ABC = 2*(angle D)
arc ABC = 2*(35)
arc ABC = 70 degrees
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break arc ABC into its smaller pieces
(minor arc AB)+(minor arc BC) = arc ABC
(38)+(minor arc BC) = 70
minor arc BC = 70-38
minor arc BC = 32
Answer: c
hope this helps!
