A quantity of 18.68 ml of a koh solution is needed to neutralize 0.1768 g of khp. what is the concentration (in molarity) of the

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bonufazy [111]

3 years ago

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A quantity of 18.68 ml of a koh solution is needed to neutralize 0.1768 g of khp. what is the concentration (in molarity) of the

koh solution? (the molar mass of khp is 204.2 g/mol.)

Social Studies

1 answer:

Svetlanka [38] · Answer 1 · 2022-03-30T18:53:58+03:00

<span>0.04635 First, calculate the number of moles of KHP you have by dividing the mass by the molar mass. 0.1768 g / 204.2 g/mol = 0.0008658 mol Since it takes 1 mole of KOH to neutralize 1 mole of KHP, that means that the 18.68 ml of the KOH solution had 0.0008658 moles of KOH. Since molarity is defined as the number of moles per liter, divide the number of moles by the volume of solution (in liters). So 0.0008658 mol / 0.01868 l = 0.04635 mol/l So the molarity of the KOH solution is 0.04635</span>