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alexandr402 [8]
3 years ago
11

The electronegativity values of fluorine, oxygen, and hydrogen are compared in the table. Comparison of Electronegativity Elemen

t Electronegativity Fluorine 4.0 Oxygen 3.5 Hydrogen 2.1 Which of the following statements is true about the strength of the hydrogen bonding in HF and H2O?
Chemistry
1 answer:
Dvinal [7]3 years ago
4 0

The hydrogen bonding in H₂O is stronger than that of HF

Explanation:

Hydrogen bonds are special dipole-dipole attraction in which electrostatic attraction is established between hydrogen atom of one molecule and the electronegative atom of a neighboring molecule.

  • The strength of hydrogen bonds depends on the how electronegative an atom is.
  • Electronegativity refers to the tendency of an atom to gain electrons.
  • The higher the value, the higher the tendency.
  • This why oxygen with a higher electronegativity will form a stronger hydrogen bond with hydrogen compared to fluorine.

Learn more:

hydrogen bond brainly.com/question/12408823

#learnwithBrainly

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In what type of environment would you most likely find Fish Species 1? Explain your answer.
KengaRu [80]

Answer:

Fish are more likely to hold a soft bait longer. ... Signs of small fish activity can lead you to fishing hot spots. ... Cover can be loosely defined as anything that will hide or protect the fish.

Explanation:

Fishes live in virtually all aquatic habitats. Different species of fish are adapted for different habitats: rocky shores, coral reefs, kelp forests, rivers and streams, lakes and ponds, under sea ice, the deep sea, and other environments of fresh, salt, and brackish water.

5 0
3 years ago
Read 2 more answers
When a piece of zinc metal is carefully placed in a beaker of strong acid, bubbles form on the surface of the metal and begin to
kati45 [8]

Answer:

A.  a new substance is being produced.

Explanation:

The bubbles most likely indicates that a new substance is being produced by this reaction. In essence, we describe this sort of change as chemical change.

In a chemical change, new substances are usually produced. They are accompanied by the evolution or absorption of energy.

The reaction of Zinc with a strong acid to produce bubbles on the surface of the metal indicates a chemical change and the formation of a new kind of substance.

Take for example, let zinc reacts with hydrocholoric acid, HCl;

   Zn         +      2HCl      →    ZnCl₂     +     H₂

Since Zn is higher than Hydrogen in the activity series, it will displace it from HCl and liberate hydrogen gas as a product. This will cause the bubbles observed in the reaction.

This is a chemical change and new products have been formed.

B and D are wrong because they are both physical changes.

C is wrong because no information about such is provided by the problem statement.

So, when a piece of zinc metal combines with a strong acid, a new kind of substance is produced.

8 0
2 years ago
Convert: 950 g to kg
scZoUnD [109]

Answer:your answer is 0.95

Explanation:

Because you put the number down if it is in the hundreds then put into a decimal that it is in the hundredths:)

4 0
2 years ago
Lakesha gave three tenths of her cookies to Bailey and five tenths of her cookies to Helen. What fraction of her cookies did Lak
Mashutka [201]

Answer:

a . eight tenths of her cookies

Explanation:

Let the total number of Lakesha's cookies be represented by x.

So that;

She gave three tenths to Bailey = \frac{3}{10} of x

                                                     = \frac{3x}{10}

She gave five tenths to Helen = \frac{5}{10} of x

                                                  = \frac{5x}{10}

Fraction of Lakesha's cookies given away = \frac{3x}{10} + \frac{5x}{10}

                                                      = \frac{3x+ 5x}{10}

                                                      = \frac{8x}{10}

Thus, the fraction of cookies given away by Lakesha is \frac{8}{10}.

6 0
2 years ago
7. Write the equation for the positron emission of barium-127.
ziro4ka [17]

The reaction is given by

\\ \rm\Rrightarrow {}^{127}_{56}Ba\longrightarrow {}^{0}_{+1}\beta+{}^{127}_{55}Cs

Barium goes underneath beta decay to form Ceaseum

  • Cs is very mellable element
  • It can melt on your hand
8 0
1 year ago
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