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TiliK225 [7]
3 years ago
12

How many moles are present in 281 grams of arsenic

Chemistry
1 answer:
Murljashka [212]3 years ago
6 0
The molar mass or As is 74.9g. Start with 281g multiply by (1mol/74.9g) = 3.75 mols

Put what you don’t want on the bottom (in this case grams) so they the u it’s cancel (if you multiply by grams and the divide by grams they cancel. Ultimately leave what you want on the top ( This case mols) then do the math
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Names of nitrogenousbonucleic bases in dna
Crazy boy [7]

Explanation:

The four nitrogenous bases present in DNA are adenine (A), guanine (G), cytosine (C) and thymine (T).

5 0
3 years ago
What is the pH of a 8.7 x 10^-12 M OH- solution ? pH= ?
vivado [14]
PH=14-pOH

pOH=-lg[OH⁻]

pH=14+lg[OH⁻]

pH=14+lg(8.7*10⁻¹²)=14-11.06=2,94
5 0
3 years ago
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Will give brainlsit need answers asap!
k0ka [10]

Answer:

120 g of NaCl in 300 g H20   at 90 C

Explanation:

At x = 90   go vertical to the line for NaCl...then go left to the y-axis to find the solubility in 100 g H20   = 40

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7 0
2 years ago
A standard solution contained 0.8 mg/mL. A student took 2 mL of the standard solution and added 10 mL of water. What is the new/
galben [10]
To get the concentration of the second solution let us use the following formulae

C1V1=C2V2 where C1 is concentration of first solution and V1 is the volume of solution first solution. on the other hand C2 is the concentration of second solution and V2 is the volume of second solution.

therefore

0.8×2=(2+10)×C2
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1.6/12=C2
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7 0
3 years ago
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How many moles of iron(III) hydroxide precipitate will form when 2.7 moles of aqueous sodium hydroxide reacts completely with ex
aalyn [17]

Answer:

0.9 mole of Fe(OH)3.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is given below:

Fe(NO3)3 + 3NaOH —> Fe(OH)3 + 3NaNO3

Now, we can determine the moles of iron (III) hydroxide formed from the reaction as follow:

From the balanced equation above,

3 moles of NaOH reacted to produce 1 mole of Fe(OH)3.

Therefore, 2.7 moles of NaOH will react to produce = 2.7/3 = 0.9 mole of Fe(OH)3.

Therefore, 0.9 mole of Fe(OH)3 is produced from the reaction.

7 0
3 years ago
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