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3 years ago

How many moles are present in 281 grams of arsenic

1 answer:

6 0

The molar mass or As is 74.9g. Start with 281g multiply by (1mol/74.9g) = 3.75 mols

Put what you don’t want on the bottom (in this case grams) so they the u it’s cancel (if you multiply by grams and the divide by grams they cancel. Ultimately leave what you want on the top ( This case mols) then do the math

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Cars run on gasoline, where octane (C8H18) is the principle component. This combustion reaction is responsible for generating en

Bezzdna [24]

Answer:

10.19 g CO₂

4.69 g H₂O

Explanation:

The combustion reaction of Octane is:

C₈H₁₈ → 8CO₂ + 9H₂O

To calculate the mass of CO₂ and H₂O produced, we need to know the mass of octane combusted.

We calculate the mass of Octane from the given volume and density, using the following conversion factors:

1 gallon = 3.785 L

1 L = 1000 mL

Now we convert 1.24 gallons to mL:

1.24 gallon * $\frac{3.785L}{1gallon} *\frac{1000mL}{1L} =$ 4693.4 mL

We calculate the mass of Octane:

4693.4 mL * 0.703 g/mL = 3.30 g Octane

Now we use the stoichiometric ratios and molecular weights to calculate the mass of CO₂ and H₂O:

CO₂ ⇒ 3.30 g Octane ÷ 114g/mol * $\frac{8molCO_{2}}{1molOctane}$ * 44 g/mol = 10.19 g CO₂

H₂O ⇒ 3.30 g Octane ÷ 114g/mol * $\frac{9molH_{2}O}{1molOctane}$ * 18 g/mol = 4.69 g H₂O

7 0

3 years ago

At 700 K, the reaction2SO2(g) + O2(g) 2SO3(g)has the equilibrium constant Kc = 4.3 x 106, and the following concentrations are p

dedylja [7]

Explanation:

The given reaction is as follows.

$2SO_{2} + O_{2}(g) \rightarrow 2SO_{3}(g)$

Value of equilibrium constant is given as $K_{c}$ = 4.3 \times 10^{6}[/tex].

Concentration of given species is $[SO_2]$ = 0.010 M; $[SO_3]$ = 10.M; $[O_2]$ = 0.010 M.

Formula for experimental value of equilibrium constant (Q) is as follows.

Q = $\frac{[SO_{3}]^{2}}{[SO_{2}]^{2}[O_{2}]}$

Putting the given concentration as follows.

Q = $\frac{[SO_{3}]^{2}}{[SO_{2}]^{2}[O_{2}]}$

Q = $\frac{(10)^{2}}{(0.010)^{2}(0.010)}$

Q = $10^{8}$

It is known that when Q > $K_{eq}$ , then reaction moves in the backward direction.

When Q < $K_{eq}$ , then reaction moves in the forward direction.

When Q = $K_{eq}$ , then reaction is at equilibrium.

As, for the given reaction Q > $K_{eq}$ then it means reaction moves in the backward direction.

Thus, we can conclude that the reaction is moving in the backward direction, that is, right to left to reach the equilibrium.

5 0

3 years ago

Which statements are true about light waves? (Select all that apply.)

Diano4ka-milaya [45]

Answer:

A C D I believe

Explanation:

4 0

2 years ago

A container of oxygen with a volume of 60 L is heated from 300 K to 400 k, What is the new volume?

Lunna [17]

Answer:

80L

Explanation:

V1/T1 = V2/T2

V2 = V1 T2/T1

T1 = 300K

V1 = 60L

T2 = 400K

V2 = ?

V2 = V1 T2/T1

V2 = (60L)(400K) / (300K)

V2 = 80L

7 0

2 years ago

Calculate the mass (in grams) of 8.56 moles of sulfur.

oksano4ka [1.4K]

Answer:

275g

Explanation:

Depending on the molar mass you are given, you can use that to solve this.

(I'm going based on my science class' molar mass of sulphur being 32.07g/mol)

Starting off, the formula for finding moles is

n=m/M (moles = mass / molar mass)

We can manipulate this equation to solve for mass.

m=Mn

now fill in what we now.

m = 32.07*8.56

mass = 274.5192

Now round for significant digits (if you are needed to do)

mass = 275g

5 0

2 years ago